False, trigonometry is not the study of three dimensional shapes.
Here we're presented with a quadratic equation which needs to be expanded and then rewritten in descending powers of x:
1x^2 + m^2x^2 + 6mx + 9 - 3 = 0.
Let's group like terms: 1x^2 + m^2x^2 + 6mx + 6 = 0.
The first 2 terms can be rewritten as a single term: (1+m^2)x^2, and so we now have:
(1+m^2)x^2 + 6mx + 6 = 0.
We must now calculate the discriminant and set the resulting expression = to 0, as a preliminary to finding the value of m for which the given quadratic has equal roots:
discriminant: (6m)^2 - 4(1+m^2)(6) = 0
Then 36m^2 - 24(1+m^2) = 0, which simplifies to 12m^2 - 24 = 0.
Then 12 m^2 = 24; m^2 = 2, and m = √2.
When the discriminant is zero, as it is here when m = √2, then the given quadratic has two equal roots.
Answer:
The possible dimensions are (21 ,2) , (3,14) , (1,42) , (6,7)
Step-by-step explanation:
Let the dimensions of the rectangle be X and Y.
Therefore if we find the factors of 42 we will get the dimensions of the triangle.
factors of rectangle are (21,2) , (3,14) , (1,42) , (6,7).
therefore possible dimensions are (21,2) , (3,14) , (1,42) , (6,7).
Greeting!
15x² = x + 2
15x² - x -2= 0
Factor left side
(5x-2)(3x+1)=0
Set factors equal to 0
5x - 2 = 0 or 3x + 1 -0
x = 2/5 or x= -1/3
I hope that helps!
Brainlest answer :)
Step-by-step explanation:
area = ( base 1 + base 2 ) ÷ 2 x height
50 = ( 10 + 15) ÷2 x height
50 ÷ 12.5 = height
height = 4