Answer:
1 plane
Step-by-step explanation:
Let's suppose the number of planes waiting or on the runway " P "
the number of planes taking off per hour ' 
'
the time for waiting and the runway 
so:
P = x
= 18 airplanes per hour
we know that 1 min = 60s
36s = 36/60 = 0.6 min
Also, 3 min and 30 s = 3 + 30/60 = 3.5 min
Next to find the time for waiting and the runway
∴= 0.6 + 3.5 = 4.1 min/60 (converting into hour)
= 0.068 hour
P = 18x0.068 = 1.23
therefore, there is 1 plane either on the runway or waiting to take off
So, there is 1 plane either on the runway or waiting to take off
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24a+48=18a-36
24a-18a=-36-48
6a=-74
a=-74/6
a=-37/3
Answer:
the probability of selecting a yellow is 4 out of 20
Answer:
13 hours
Step-by-step explanation:
Average speed = Distance traveled / time taken
⇒ Distance = Average speed × Time
d = s × t
For the first trip;
Average speed = 280 mph
d₁ = 280t₁ ------(1)
where;
d₁ is the distance covered to get to the destination
t₁ is the time taken to get to the destination
For the second trip;
Average speed = 240 mph
d₂= 240t₂ ------(2)
where;
d₂ is the distance covered on the way back
t₂ is the time taken on the way back
The trip is the same distance to and fro. Therefore,
d₁ = d₂
Substituting the equation for d₁ and d₂
280t₁ = 240t₂ ------(3)
It took one hour less time to get there than it did to get back, then,
t₁ = t₂ - 1
t₂ = t₁ + 1 ------(4)
Substituting equation (4) into equation (3)
280t₁ = 240(t₁ + 1)
280t₁ = 240t₁ + 240
280t₁ - 240t₁ = 240
40t₁ = 240
t₁ = 240/40
t₁ = 6 hours
From equation (4)
t₂ = t₁ + 1
t₂ = 6 + 1
t₂ = 7 hours
The total time for the trip is t₁ + t₂ = 6 + 7
= 13 hours
Isolate the p. First, add 16 to both sides
3p - 16 (+16) < 20 (+16)
3p < 36
Next, isolate the p. Divide 3 from both sides
3p/3 <36/3
p < 12
p < 12 is your answer
hope this helps
