Answer:
Option A
They are located near the equator
Explanation:
From the diagram, we can observe that all the rain forest zones occur near the equator.
This is because on an annual basis, the equator receives the highest concentration of solar radiation in the whole Earth. This implies that the rate of evaporation of water from the water bodies present is high, and consequently, the amount of rainfall is high also. This abundant sunshine and high rainfall leads to the growth of the tropical rain forests at those regions
Answer:
During the prophase of mitosis, the chromatin in a cell compacts to form condensed chromosomes; this condensation is required in order for the cell to divide properly. While mitotic cells have condensed chromosomes, interphase cells do not.
Explanation:
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Answer:
d. The gold(III) ion is most easily reduced.
Explanation:
The standard reduction potentials are
Au³⁺ + 3e⁻ ⟶ Au; 1.50 V
Hg²⁺ + 2e⁻ ⟶ Hg; 0.85 V
Zn²⁺ + 2e⁻ ⟶ Zn; -0.76 V
Na⁺ + e⁻ ⟶ Na; -2.71 V
A <em>more positive voltage</em> means that there is a <em>stronger driving force</em> for the reaction.
Thus, Au³⁺ is the best acceptor of electrons.
Reduction Is Gain of electrons and, Au³⁺ is gaining electrons, so
Au³⁺ is most easily reduced.
Answer:
Methods of soil conservation are listed below.
Explanation:
The major sources of soil erosion include water,wind and tillage. In order to mitigate or prevent soil erosion, some of the following techniques can be implemented:
- <u>Contour Farming: </u>Planting in row patterns that run level around a hill — as opposed to the up and down the slope pattern.This reduces runoffs and consequently water erosion.
- <u>Crop Rotation:</u> This involves planting crops with high residue (e.g corn, small grains, e.t.c) in rotation,as the layer of residue would protect the topsoil.
- <u>Built in structural diversion</u> : Used often for gully control, to regulate flow of water away from the field and through designated desired paths.
- <u>Conservation Tillage</u>: This involves methods such as no-till planting, strip rotary tillage, etc, which do not allow the soil surface to be smooth and bare, but instead covered with crop residue that protects the soil from eroding forces.
The density is 4 g/cm³ or 4000 kg/m³.
Density = mass/volume = 12 g/3 cm³ = 4 g/cm³
The measurement of 4 g/cm³ is already in <em>SI units</em>.
In SI <em>bas</em>e units,
Density = (4 g/1 cm³) × (1 kg/1000 g) × (100 cm/1 m)³ = 4000 kg/m³
