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Nezavi [6.7K]
3 years ago
10

When heated, KClO3 decomposes into KCl and O2. KClO3--> 2KCl+ 3O . If this reaction produced 62.6 g of KCl, how much O2 was p

roduced (in grams)?
Chemistry
1 answer:
Vladimir [108]3 years ago
5 0
The solution to your problem is as follows:

 <span>2 KClO3 → 2 KCl + 3 O2 

</span><span>MW of KCL = 39.1 + 35.35 = 74.6 g/mole 

62.6/74.6 = 0.839 moles KCl produced 

0.839 moles KCl x 3O2/2KCl x 32g/mole O2 = 40.27g of O2 was produced
</span>
Therefore, there are <span>40.27g of O2 produced during the reaction.
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly.


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