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larisa [96]
3 years ago
9

How does the chemical formula relate to the number of particles that result from the dissociation of molecule?

Chemistry
1 answer:
Mazyrski [523]3 years ago
5 0
The chemical formula would dictate how many ions are present in a solution. It tells how many of what ion would dissociate in the solution. In every chemical reaction or dissociation reaction, it is important to remember that the number of each atoms on each side would be equal. 
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You plan to separate a polar and a non-polar compound using normal phase column chromatography technique. Methylene chloride (CH
marissa [1.9K]

Answer:

Hexane should be used first.

Explanation:

Chromatography is a method of separating the constituents of a mixture by taking advantage of their different rates of movement in a solvent over an adsorbent medium. Chromatography is a means of separation and analysis that utilises fractional separation. It is based on the principle  that if a fluid containing a number of substances is allowed to pass though an adsorbent medium, the different substances in the fluid may travel at different rates and be separated.

The rate of movement depends on the relative affinities of the constituents for the solvent and adsorbent medium. i.e solutes which are weakly adsorbed by the adsorbent medium are easily redissolved by the ascending solvent and quickly travel up the adsorbent medium. In addition to that , solutes which are very soluble in the solvent move up at a faster rate than those which  are not soluble.

In column Chromatography;

A non-polar solvent should be initiated and applied first. This is because , in a column chromatography, a non-polar compound will be removed at first then later polar compound.

Assuming a polar compound is used first, the polar compounds will be removed alongside with all the non-polar compounds.

From the two Compounds given;

We know that :

Hexane is a non-polar compound and Methylene chloride  is a polar compound. As such, Hexane should be used first.

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3 years ago
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<h3>0.2498molN_{2}</h3>

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