Answer:
B
Step-by-step explanation:
this is just common sense. if you would have tried you could have easily answered this yourself.
the sequence starts with 6. that is a1.
so, the formula simply has to add "something" to 6.
therefore, A and D are out.
and then we see immediately that the sequence is built by subtracting 4 (or adding -4) for every step.
so, we need to add multiples of -4.
therefore, only B is correct (C adds multiples of +4).
Answer:
Answer is 2
Step-by-step explanation:
Answer: 37.68 feet
Step-by-step explanation:
Answer:
There are no errors
Step-by-step explanation:
The math is correct
Answer:
The nonzero vector orthogonal to the plane is <-9,-8,2>.
Step-by-step explanation:
Consider the given points are P=(0,0,1), Q=(−2,3,4), R=(−2,2,0).


The nonzero vector orthogonal to the plane through the points P,Q, and R is


Expand along row 1.




Therefore, the nonzero vector orthogonal to the plane is <-9,-8,2>.