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nataly862011 [7]
3 years ago
8

In a college election, the winning candidate got 58% of the 368 votes that were cast. How many votes did the winner received.

Mathematics
1 answer:
Anastasy [175]3 years ago
8 0

58% of 368 is nothing but .58 x 368


.58 x 368 = 213.44


So, the winning candidate got 213.44 votes


Hope this answers your question! :)

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What is the total cost of a $56.53 meal at a restaurant after including a 17% tip?
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The total cost is $66.14. Hope this helps.
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11. David's net worth is $45,765.78 and his assets have a value of
MArishka [77]

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the last one

Step-by-step explanation:

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Read 2 more answers
Plz help!! A jar contained 6 red marbles, 10 green marbles, and 8 blue marbles. A marble was selected at random, the color was r
Inessa [10]

Answer:

To calculate the relative frequency, first we need to know what exactly is and how to calculate it.

Relative frequency is the ratio between the absolute frequency (how many repetitions have a specific outcome) and the total outcomes. Also, this type of frequency is used to show the representation that some data have over the whole distribution.

So, in this case, we need to just divide 13, which belongs to red marble's results, to 60 which is the total outcomes, as it's presented:

         13redmarble                                                                                                                       Fr = -------------------------

       60 totalmarbles  

Normally, relative frequency is shown as a percentage multiplying this result by 100. Therefore, 22% is the approximate percentage of the relative frequency, which means that 22% is the representation of red marbles outcomes of the whole distribution, or we can say it as a probability: there's 22% of chances when someone extract a marble, it will be red.

3 0
3 years ago
Let A and B be events with =PA0.7, =PB0.3, and =PA or B0.9. (a) Compute PA and B. (b) Are A and B mutually exclusive? Explain. (
kvasek [131]

Answer:

a) P(A \cup B) = P(A) +P(B) - P(A\cap B)

And if we solve for P(A \cap B) we got:

P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1

b) False

The reason is because we don't satisfy the following relationship:

P(A\cup B) = P(A) + P(B)

We have that:

0.9 \neq 0.3+0.7 =1

c) False

In order to satisfy independence we need to have the following condition:

P(A \cap B) = P(A) *P(B)

And for this case we don't satisfy this relation since:

0.1 \neq 0.7*0.3 = 0.21

Step-by-step explanation:

For this case we have the following probabilities given:

P(A) = 0.7, P(B) =0.7, P(A \cup B) =0.9

Part a

We want to calculate the following probability: P(A \cap B)

And we can use the total probability rule given by:

P(A \cup B) = P(A) +P(B) - P(A\cap B)

And if we solve for P(A \cap B) we got:

P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1

Part b

False

The reason is because we don't satisfy the following relationship:

P(A\cup B) = P(A) + P(B)

We have that:

0.9 \neq 0.3+0.7 =1

Part c

False

In order to satisfy independence we need to have the following condition:

P(A \cap B) = P(A) *P(B)

And for this case we don't satisfy this relation since:

0.1 \neq 0.7*0.3 = 0.21

4 0
4 years ago
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