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2 years ago

Make an equation for the line v=(6,6) is perpendicular to y=-2/3x-11

Mathematics

1 answer:

natali 33 [55]2 years ago

5 0

Answer:

y=-2/3x+10

Step-by-step explanation:

y=2/3x-11

plug in plot and remove intercept

6=-2/3(6)+b

6=-4+b

10=b

y=-2/3x+10

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Jose has 4 friends and 3 apples how much would each friend get if he shared

blsea [12.9K]

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3 years ago

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A 13foot lader i upagenst a tree the bottom of the ladder is 5 feet away form the tree how high is the ladder on the tree

SCORPION-xisa [38]

Think of the 13-ft length of the ladder as the hypotenuse of a right triangle. Represent the horiz. distance from foot of ladder to base of tree by x, or 5 ft.

Represent the vert. dist. from base of tree to top of ladder by y, which is unknown.

Then (13 ft)^2 = (5 ft)^2 + y^2, or

169 ft^2 = 25 ft^2 + y^2. This simplifies to y^2 = 144. Thus y = + 12 feeet.

Note: Please pay attention to your spelling: "lader i up agenst a tree" should be "the top of a 13-ft ladder is placed against a tree."

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3 years ago

Can u plz show work?Only need 84

Sonbull [250]

Answer:

Step-by-step explanation:

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3 years ago

the temperature of the water in Emily's fish tank was 78 degrees F on Sunday the water temperature was changed by -3 on Monday a

SpyIntel [72]

To solve this problem, let us analyze this step by step. The temperature for each day is as follows:

Water temperature on Sunday = 78 degrees F

Water temperature on Monday = changed by -3 degrees F

Water temperature on Tuesday = changed by 3 degrees F

We can see that the total change of water temperature from Sunday to Tuesday is:

-3 + 3 = 0

Therefore there is zero overall change. There the integer which represents the temperature change is “0”.

Since the overall change in water temperature is zero, hence the temperature on Sunday and on Tuesday is similar.

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3 years ago

Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective

soldier1979 [14.2K]

Answer:

a) $P[C]=p^n$

b) $P[M]=p^{8n}(9-8p^n)$

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

$P[C]=p^n$

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

$P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)$

$P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9$

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

$P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2$

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.

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3 years ago