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Kryger [21]
3 years ago
13

What is the proportion of 3/5=7/x

Mathematics
2 answers:
otez555 [7]3 years ago
8 0
The answer is x equal 11.5
Sloan [31]3 years ago
5 0
3/5=7/x  multiply both sides by x

3x/5=7  multiply both sides by 5

3x=35  divide both sides by 3

x=35/3 or if you prefer 11 2/3
You might be interested in
What is the answer to x/3+8=-2
Bingel [31]

Answer:

x = - 30

Step-by-step explanation:

x/3  + 8 = - 2     subtract 8 from both sides of the equation

x/3 = -2 - 8 = -10  now multiply both sides by 3

x = -30

3 0
2 years ago
A.3.5 <br><br> B.-2.5<br><br> C.-5.5<br><br> D.2.5
mart [117]
The answer is 2.5 because the point is on -1.5, so -1.5+4=2.5
7 0
3 years ago
Evaluate |-11| + |-7|.<br><br> -18<br> -4<br> 4<br> 18
Marta_Voda [28]

Answer:  D) 18

======================================================

Explanation:

|-11| simplifies to 11

|-7| simplifies to 7

Whatever is inside the absolute value, you just remove the negative and that's the result of that absolute value expression. It represents the distance on a number line. So for instance -11 is 11 units from 0, which is why |-11| = 11.

Overall,

|-11| + |-7| = 11 + 7 = 18

4 0
2 years ago
Enter the coordinates of the vertices of r(180,0) and t(3,-2) (QRST) will give crown
Viktor [21]

Answer:

Step-by-step explanation:

From the graph attached,

Coordinates of the vertices are,

Q(1, 3), R(3, -3), S(0, -2) and T(-2, 1)

Following the rule of translation by 3 units to the right and 2 units down T_{(3, -2)}

(x, y) → (x+3, y-2)

Q(1, 3) → Q''(4, 1)

R(3, -3) → R"(6, -5)

S(0, -2) → S"(3, -4)

T(-2, 1) → T"(1, -1)

Following rule r_{(180,\text{O})} (rotation of a point by 180° about the origin) will give the image points,

(x, y) → (-x, -y)

Q"(4, 1) → Q'(-4, -1)

R"(6, -5) → R'(-6, 5)

S"(3, -4) → S'(-3, 4)

T"(1, -1) → T'(-1, 1)

7 0
3 years ago
If the function h is defined by h(x)=<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" a
harkovskaia [24]

Given:

The function is:

h(x)=x^2-3x+5

To find:

The value of h(2x+1).

Solution:

We have,

h(x)=x^2-3x+5

Putting x=2x+1, we get

h(2x+1)=(2x+1)^2-3(2x+1)+5

h(2x+1)=(2x)^2+2(2x)(1)+(1)^2-3(2x)-3(1)+5

h(2x+1)=4x^2+4x+1-6x-3+5

On combining like terms, we get

h(2x+1)=4x^2+(4x-6x)+(1-3+5)

h(2x+1)=4x^2-2x+3

Therefore, the required function is h(2x+1)=4x^2-2x+3.

3 0
3 years ago
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