All categories

3 years ago

The attraction or repulsion of two objects is called blank force what is the blank

Physics

1 answer:

AysviL [449]3 years ago

5 0

Answer:

Coulomb Force

Explanation:

Coulomb force, also called electrostatic force or Coulomb interaction, attraction or repulsion of particles or objects because of their electric charge.

You might be interested in

Calculate: The time taken for a plane to travel 3,000 km at a speed of 200 m/s

Alborosie

Time = (distance) / (speed)

Distance = 3,000 km = 3,000,000 meters

Speed = 200 m/s

Time = (3,000,000 m) / (200 m/s)

Time = 15,000 seconds

That's 4 hours 10 minutes

6 0

3 years ago

Planets in our solar system do not revolve around the sun in perfect circles. Their orbits are more like ovals that scientists d

galben [10]

Planets in our solar system do not revolve around the sun in perfect circles. Their orbits are more like ovals that scientists describe as elliptical. It is one of Kepler's laws. The sun is the focus of all the planets. The correct answer is D.

7 0

4 years ago

Unicellular organism are

tatyana61 [14]

Explanation:

Its organism are one cell I think

8 0

3 years ago

I need help on this physics problem.

Alex

Answer:

the speed of the nerve impulse in miles per hour is 201.59 mi/hr

Explanation:

Given;

the speed of the nerve impulse, v = 90.1 m/s

To convert this speed in meters per second to miles per hour, we use the following method;

1,609 meter = 1 mile

3,600 s = 1 hour

$v(mi/h) = 90.1 \ \frac{m}{s} \times \frac{1 \ mile}{1,609 \ m} \times \frac{3,600 \ s}{1 \ hour} = (\frac{90.1 \times 3,600}{1,609} )\frac{mi}{hr} = 201.59 \ mi/hr$

Therefore, the speed of the nerve impulse in miles per hour is 201.59 mi/hr

6 0

3 years ago

block of mass 5kgriding on a horizontal frictionlessxy-plane surface is subjected tothree applied forces:→F1= 12√2N[ 45◦]→F2= (8

dsp73

Answer:

(i) See attached image for the drawing

(ii) net force given in component form: (20, 20)N with magnitude: $\sqrt{800} \,\,\,N$

Explanation:

First try to write all forces in vector component form:

The force F1 acting at 45 degrees would have multiplication factors of $\frac{\sqrt{2} }{2}$ on both axes, to take care of the sine and cosine projections. Therefore, the:

x-component of F1 is $F1_x=12\,\sqrt{2} \frac{\sqrt{2} }{2} =12\,\,N$

y-component of F1 is $F1_y=12\,\sqrt{2} \frac{\sqrt{2} }{2} =12\,\,N$

As far as force F2, it is given already in x and y components, then:

x-component of F2 = 8 N

y-component of F2 = -6 N (negative meaning pointing down the y-axis)

Force F3 has only component (upwards) in the y-direction

x-component of F3 = 0 N

y-component of F3 =14 N

The additions of all these component by component, gives the resultant force (R) acting on the 5 kg mass:

x-component of R = 12 + 8 = 20 N

y-component of R = 12 + 14 - 6 = 20 N

Therefore, the acceleration that the mass receives due to this force is given in component form as:

x-component of acceleration: 20 N / 5 kg = $4\,\,\,m/s^2$

y-component of acceleration: 20 N / 5 kg = $4\,\,\,m/s^2$

Now we can calculate the components of the velocity of this mass after 2 seconds of being accelerated by this force, using the formula of acceleration times time:

x-component of the velocity is: $v_x=4\,*\,2=8\,m/s$

y-component of the velocity is: $v_y=4\,*\,2=8\,m/s$

7 0

4 years ago