A distance of 2.00 mm separates two objects of equal mass. If it gravitational force between them is 0.0104 N, find the mass of
1 answer:
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Answer:
a) t =12[s]; b) x = 348[m]
Explanation:
We can solve this problem using the following kinematics equations:
a)
where:
vf = final velocity = 12 [m/s]
vo= initial velocity = 6 [m/s]
a = acceleration = 0.5[m/s^2]
t = time [s]
Now clearing the time t, we have:
b)
We can calculate the displacement for the first 12 [s] then using the equation for the constant velocity we can calculate the other displacement for the 20[s].
The we can calculate the second displacement for the constant velocity:
x = x1 + x2
x = 108 + 240
x = 348[m]