Answer: Option 3.
Explanation:
Formula for kinetic energy is
K.E = (1 / 2) * (m * v ^ 2)
Assuming mass to be constant,
We can see that K.E is proportional to v^2.
It means that when you substitute the value of velocity in v, kinetic energy increases with v^2.
Option 1 and 2 are eliminated because the relationship between kinetic energy and velocity in the graph is shown as linear. We already know from formula that the relationship is not linear.
Option 4 is incorrect because kinetic energy must be zero when velocity is zero. This graph shows kinetic energy is becoming infinite as velocity tends to 0.
So option 3 is correct answer.
Answer:
Effective Pulling Force = 29.2(cos 62.7°) = 13.393 N
Resistance to Pulling Force = 11.7 N
Net Force acting on suitcase = 13.393 - 11.7 = 1.693 N
Distance moved = 8.44 m
Net Work = 1.693(8.44) = 14.289 ≈ 14.3 J ANS
Explanation:
hope that makes sense homie
Answer:
2.26l
Explanation:
From the general gas equation:
P1V1/T1 = P2V2/T2
Since pressure remained constant we can say:
V1/T1 = V2/T2
so to convert to kelvin add 273 to both temperature values then we can say:
1 m^3= 1000 L
2l=0.002m^3
Then;
0.002/308=V/348
V=(0.002/308)348
Final volume=0.002259m^3
=2.6l(1 decimal place)
We are given that the wavelength ʎ is from 400 nm to 700
nm. The formula for this is:
d sin a =m * ʎ
where,
d = slit separation = 1 mm / 750 lines = 1/750
a = angle
m = 1
ʎ = 400 nm to 700 nm = 0.0004 mm to 0.0007 mm
Rewriting the formula in terms of angle a:
a = sin^-1 (m ʎ / d)
when ʎ = 0.0004 mm
a = sin^-1 (0.0004 / (1/750))
a = 17.46°
when ʎ = 0.0007 mm
a = sin^-1 (0.0007 / (1/750))
a = 31.67°
Hence the range of angles is from 17.46° to 31.67<span>°.</span>
Answer:
Magnetic field, 
Explanation:
Given that,
Velocity of electron, 
It enters a region of space where perpendicular electric and a magnetic fields are present.
Magnitude of electric field, 
We need to find the magnetic field will allow the electron to go through the region without being deflected.
Magnetic force on the electron, 
.......(1)
Electric force on the electron, F = q E........(2)
From equation (1) and (2) we get:
B = 0.0002 T
or
Hence, this is the required solution.
