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Galina-37 [17]
4 years ago
14

There are many types of significant lines in blueprint reading. Which line defines the walls and surface boundaries of prints?

Physics
1 answer:
tresset_1 [31]4 years ago
3 0

Answer: Thick Continous Lines

Explanation:

In blue print reading, there are many types of significant lines with unique meanings and usages.

The thick continuous line is used to represent surface boundaries or solid objects.

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__are particles without electric charge in the atom's nucleus.
gladu [14]

Answer:

neutrons

Explanation:

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Determine the acceleration of a raptor that reaches 25 m/s from rest in 6.5 s.
REY [17]

Answer:

3.8 m/s²

Explanation:

Average acceleration is the change in velocity over change in time.

a = Δv / Δt

a = (25 m/s − 0 m/s) / 6.5 s

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8 0
4 years ago
These problems involve Impulse-Mometum theorem, and the Work-Kinetic Energy theorem. Both theorems are combinations of Newton's
ira [324]

a) The time needed to stop the car is 82.5 s

b) The final speed of the bullet is 23,625 m/s

Explanation:

a)

We can solve this part of the problem by using the impulse-momentum theorem, which states that:

"The impulse exerted on an object (the product between force applied and time interval) is equal to the change in momentum of the object"

Mathematically:

F\Delta t = m\Delta v

where

F is the force applied

\Delta t is the time interval

m is the mass of the object

\Delta v is the change in velocity

For the train car in this problem, we have

m = 16000 kg is the mass

F = -1900 N is the force applied (with negative sign, since it is applied in the direction opposite to the direction of motion, in order to stop the train)

\Delta v = 0 -9.8 m/s = -9.8 m/s is the change in velocity of the car

Solving for \Delta t, we find the time needed:

\Delta t = \frac{m\Delta v}{F}=\frac{(16000)(-9.8)}{-1900}=82.5 s

b)

Again, in this part we can also use the impulse-momentum theorem:

F\Delta t = m\Delta v

where

F is the force applied

\Delta t is the time interval

m is the mass of the object

\Delta v is the change in velocity

For the bullet in this problem, we have:

m = 0.027 kg is the mass

F = 3500 N is the force applied

\Delta t = 0.004 s is the time interval

Solving for \Delta v, we find the change in velocity of the bullet:

\Delta v = \frac{F \Delta t}{m}=\frac{(3500)(0.027)}{0.004}=23,625 m/s

And since the initial velocity of the bullet is zero, the final velocity (and speed) is

v=23,625 m/s

Learn more about impulse and momentum:

brainly.com/question/9484203

#LearnwithBrainly

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3 years ago
Why is the escape speed for a spacecraft independent of the spacecraft's mass?
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