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4 years ago

8

At this temperature, 0.300 mol H 2 0.300 mol H2 and 0.300 mol I 2 0.300 mol I2 were placed in a 1.00 L container to react. What

concentration of HI HI is present at equilibrium?

1 answer:

Alekssandra [29.7K]4 years ago

5 0

Answer:

The concentration of HI present at equilibrium is 0.471 M.

Explanation:

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How long does it take to electroplate 0.5 mm of gold on an object with a surface area of 31 cm^^ from an Au3+(aq) solution with

konstantin123 [22]

Answer:

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

Explanation:

Mass of gold = m

Volume of gold = v

Surface area on which gold is plated = $a=31 cm^2$

Thickness of the gold plating = h = 0.5 mm = 0.05 cm

1 mm = 0.1 cm

$V=a\times h=31 cm^2\times 0.05 cm=1.55 cm^3$

Density of the gold = $d=19.3 g/cm^3$

$m=d\times v=19.3 g/cm^3\times 1.55 cm^3=29.915g$

Moles of gold = $\frac{29.915 g}{197 g/mol}=0.152 mol$

$Au^{3+}+3e^-\rightarrow Au$

According to reaction, 1 mole of gold required 3 moles of electrons,then 0.152 moles of gold will require :

$\frac{3}{1}\times 0.152 mol=0.456 mol$ of electrons

Number of electrons = N = $0.456\times \times 6.022\times 10^{23}$

Charge on single electron = $q=1.6\times 10^{-19} C$

Total charge required = Q

$Q=N\times q$

Amount of current passes = I = 8 Ampere

Duration of time = T

$I=\frac{Q}{T}$

$T=\frac{N\times q}{I}$

$=\frac{0.456\times \times 6.022\times 10^{23}\times 1.6\times 10^{-19} C}{8 A}=5492 s$

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

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True or false transuranium elements are synthetic elements with atomic #’s of 93 or higher.

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What is the purpose of the uninoculated control tubes used in the oxidation fermentation test?

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3 years ago

How many grams of K2Cr207 are in 250. mL of 0.500M of K2Cr207:

goldenfox [79]

<u>Analysing the Question:</u>

We are given a 250 mL solution of 0.5M K₂Cr₂O₇

Which means that we have:

0.5 Mole in 1L of the solution

0.125 moles in 250 mL of the solution <em>[dividing both the numbers by 4]</em>

<em />

<u>Mass of K₂Cr₂O₇ in the given solution:</u>

Molar mass of K₂Cr₂O₇(Potassium Dichromate) = 194 g/mol

<em>we know that we have 0.125 moles in the 250 mL solution provided</em>

Mass = Number of moles * Molar mass

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