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3 years ago

8

At this temperature, 0.300 mol H 2 0.300 mol H2 and 0.300 mol I 2 0.300 mol I2 were placed in a 1.00 L container to react. What

concentration of HI HI is present at equilibrium?

1 answer:

Alekssandra [29.7K]3 years ago

5 0

Answer:

The concentration of HI present at equilibrium is 0.471 M.

Explanation:

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How many protons z and how many neutrons n are there in a nucleus of the most common isotope of silicon, 2814si? separate your a

Maksim231197 [3]

The Atomic Number and Atomic Mass of ²⁸Si₁₄ are 14 and 28 respectively.

Atomic Number:
Atomic Number of Element is the Number of Protons contained by the Element. So, there are 14 Protons in ²⁸Si₁₄.

Atomic Mass:
Atomic Mass of Element is the total number of Protons and Neutrons present in the Nucleus of that element.
So,
Atomic Mass = # of Protons + # of Neutrons

As the Atomic mass of ²⁸Si₁₄ is 28 and it has 14 protons, So # of Neutrons are calculated as,

# of Neutrons = Atomic Mass - # of Protons

# of Neutrons = 28 - 14

# of Neutrons = 14

Result:
In ²⁸Si₁₄ Number of Neutrons are 14, Number of Protons are 14.

Z = 14 , n = 14

3 0

3 years ago

The effects of acid rain include:

posledela

<span>The effects of acid rain include:

d. All the above
</span>

7 0

3 years ago

Here is the reaction of carbamic acid and ammonia to form an amide and water. There is a scheme of a reversible reaction where c

vladimir2022 [97]

Answer:

See explanation

Explanation:

I have attempted to show the sequence of the reaction between carbamic acid and ammonia to form an amide and water and urea.

The reaction first involves the protonation of ammonia to give ammonium carbamate.

When ammonium carbamate is heated to 130-140 degrees, we obtain urea and water as the final products of the reaction

4 0

3 years ago

How many liters are in 62.9 g NaOH?

Sunny_sXe [5.5K]

Answer:

39.99711 grams.

Explanation:

Moles to Grams Naoh

1 mole is equal to 1 moles NaOH, or 39.99711 grams.

5 0

3 years ago

silver has an atomic mass of 107.868 amu. silver has two common isotopes. one of the isotopes has a mass of 106.906 amu and a re

Sunny_sXe [5.5K]

A. The abundance of the 2nd isotope is 48.119%

B. The mass of the 2nd isotope is 108.905 amu

Let the 1st isotope be A

Let the 2nd isotope be B

A. Determination of the abundance of the 2nd isotope

Abundance of isotope A = 51.881%.

<h3>Abundance of isotope B =? </h3>

Abundance of B = 100 – A

Abundance of B = 100 – 51.881

<h3>Abundance of B = 48.119%</h3>

B. Determination of the mass of the 2nd isotope

Atomic mass of silver = 107.868 amu.

Mass of 1st isotope (A) = 106.906 amu

Abundance of isotope A (A%) = 51.881%.

Abundance of isotope B (B%) = 48.119%

<h3>Mass of 2nd isotope (B) =? </h3>

$atomic \: mass = \frac{mass \: of \:A \times \:A\%}{100} + \frac{mass \: of \:B \times \:B\%}{100} \\ \\ 107.868 = \frac{106.906\times \ \: 51.881}{100} + \frac{mass \: of \:B \times \:48.119}{100} \\ \\ 107.868 = \: 55.464 + 0.48119 \times mass \: of \:B \\ \\ collect \: like \: terms \\ \\ 0.48119 \times mass \: of \:B = 107.868 - 55.464 \\ \\ divide \: both \: side \: by \: 0.48119 \\ \\ mass \: of \:B = \frac{107.868 - 55.464 }{0.48119} \\ \\ mass \: of \:B =108.905 \: amu \\ \\$

Therefore, the mass of the 2nd isotope is 108.905 amu

Learn more: brainly.com/question/7955048

6 0

2 years ago