Crush the limestone... it would give more area for the acid to react
(a) In this section, give your answers to three decimal places.
(i)
Calculate the mass of carbon present in 0.352 g of CO
2
.
Use this value to calculate the amount, in moles, of carbon atoms present in 0.240 g
of
A
.
(ii)
Calculate the mass of hydrogen present in 0.144 g of H
2
O.
Use this value to calculate the amount, in moles, of hydrogen atoms present in 0.240 g
of
A
.
(iii)
Use your answers to calculate the mass of oxygen present in 0.240 g of
A
Use this value to calculate the amount, in moles, of oxygen atoms present in 0.240 g
of
A
(b)
Use your answers to
(a)
to calculate the empirical formula of
A
thank you
hope it helpsss
Answer:
A. Herbivores have longer digestive systems than carnivores have.
Explanation:
We can conclude that the herbivores have longer digestive systems compared to carnivores.
Carnivores feeds on other animals whereas herbivores eats plants.
- Most herbivores have a four stomach compartment system that helps them process and digest their food.
- This is because they have to process cellulose in plants which needs to be properly broken down.
- Flesh eating carnivores do not require this arrangement.
- The four stomach compartment of most herbivores includes Rumen, Reticulum, omasum and abomasum.
- They also chew the cud whereby they regurgitate food materials.
55 as long as Ik I think it’s 55 but I’m Sorry if it’s wrong
<u>Answer:</u> For the given reaction, the value of 
is greater than 1
<u>Explanation:</u>
For the given chemical equation:
The expression of for above equation follows:
![K_c=\frac{[Ca^{2+}]\times [CO_3^{2-}]}{[CaCO_3}]\\\\K_c=[Ca^{2+}]\times [CO_3^{2-}]](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCa%5E%7B2%2B%7D%5D%5Ctimes%20%5BCO_3%5E%7B2-%7D%5D%7D%7B%5BCaCO_3%7D%5D%5C%5C%5C%5CK_c%3D%5BCa%5E%7B2%2B%7D%5D%5Ctimes%20%5BCO_3%5E%7B2-%7D%5D)
The concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression
As, the denominator is missing and the numerator is the only part left in the expression. So, the value of will be greater than 1.
Hence, for the given reaction, the value of is greater than 1
