Answer:
ΔU° = 56.0 J
Explanation:
Step 1: Given data
- Work done to compress the gas (w): 83.0 J (When work is done on the gas, w is positive).
- Heat given off to the surroundings (q): -27.0 J (When heat is released to the surroundings, q is negative)
Step 2: Calculate the change in the internal energy of the gas (ΔU°)
The internal energy of a gas is the energy contained within it. We can calculate it using the following expression.
ΔU° = q + w
ΔU° = -27.0 J + 83.0 J
ΔU° = 56.0 J
To determine the mass, you need to know the molecular weight of the c8h10n4o2 . The molecular weight of <span>c8h10n4o2 would be: 8*12 + 10*1 + 4*14 + 2*16= 194g/mol.
To convert the number of molecules into moles, you need to divide it with 6.02 * 10^23. The calculation of the mass of </span>c8h10n4o2 would be:
(7.20×10^20 molecules) /(6.02 * 10^23 molecule/mol) * 194g/mol= 232 * 10^-3 grams= 0.232 grams
<span>sudden increase of Nitrate and Phosphate in March to April that occurred, it causes the fish tank to produce algae</span>
Answer:A
Explanation: because i saw the sheet
Answer:
1. 0.0154mole of PbS
2. Double displacement reaction
Explanation:
First, let write a balanced equation for the reaction. This is illustrated below:
Pb(CH3COO)2 + H2S —> PbS + 2 CH3COOH
Molar Mass of Pb(CH3COO)2 = 207 + 2(12 + 3 + 12 + 16 +16) = 207 + 2(59) = 207 + 118 = 325g
Mass of Pb(CH3COO)2 = 5g
Number of mole = Mass /Molar Mass
Number of mole of Pb(CH3COO)2 = 5/325 = 0.0154mole
From the equation,
1mole of Pb(CH3COO)2 produced 1mole of PbS.
Therefore, 0.0154mole of Pb(CH3COO)2 will also produce 0.0154mole of PbS
2. The name of the reaction is double displacement reaction since the ions in the two reactants interchange to form two different products
