Answer:
volume before reducing is 8 times the volume after reducing
Step-by-step explanation:
volume before reducing=
V=4/3πr³=
V=4/3π(9)³=972π cm³
diameter reduced to half=18/2=9 cm
radius=d/2=9/2=4.5 cm
volume of sphere when diameter reduced by 1/2=
V=4/3πr³
v=4/3 (π)(4.5)³=121.5π
<h2>
volume before reducing is <u>
8</u>
times the volume after reducing</h2>
Answer:
It is unclear what exaclty the kind of answer is you are looking for.
Step-by-step explanation:
adding- 11
subtracting- 1 or -1
multiplying- 30
dividing- 1.2 or 0.8333333
Pick any two pairs of equations<span> from the system. Eliminate the same </span>variable<span> from each pair using the Addition/Subtraction method. Solve the system of the two new </span>equations<span> using the Addition/Subtraction method.</span>
Answer:
Find the median value for the dataset. Find the values of the lower and upper quartiles. Find the value of the interquartile range (IQR). Identify any outliers in the dataset. Use the criterion that a value is an outlier if it is either more than 1.5 x IQR above
Answer:
2^(8p) =2^(5p+15)
Step-by-step explanation:
16 ^ 2p = 32 ^ (p+3)
Rewrite each number as a power of 2
16 = 2^4
32 = 2^5
2^4 ^ 2p =2^5 ^ (p+3)
We know a^b^c = a^(b*c)
2^(4 * 2p) =2^(5 * (p+3))
2^(8p) =2^(5p+15)
