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2 years ago

What is slope????????

Mathematics

2 answers:

Damm [24]2 years ago

8 0

Step-by-step explanation:

slope another name for gradient

enot [183]2 years ago

3 0

It's how steep a line is

to find it you would do rise/run or y2-y1/x2-x1

if u need an example or two tell me

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Help anyone can help me do this question,I will mark brainlest.

andrey2020 [161]

Answer:

8 cm

Step-by-step explanation:

AM = MC = BM = (1/2) BC => AM , MC , BM = 5, => BC = 10
apply pytago => (AC ^ 2) + (AB ^ 2) = (BC ^2)
AB = $\sqrt{BC ^2 - AC ^2}$ = $\sqrt{10 ^2 - 6 ^ 2}$ = 8 (cm)

5 0

2 years ago

Read 2 more answers

Which situation CANNOT be represented by this equation? <br><br>4x+7=314x+7=31<br><br>

vovangra [49]

Answer:

The one on the bottom CANNOT be represented by the equation.

Step-by-step explanation:

For the equation in the problem there has to be a 4x, meaning the cost per case multiplied times the about of them (x). Then there has to be a +7 somewhere in the equation for shipping. The two on the top fit both of those descriptions.

Mark Brainliest plz!

8 0

3 years ago

Simplify 5^2•5^4 pls help

Brrunno [24]

6^8 that’s the anwser

8 0

3 years ago

17. Factor x ^ 3 + 5x ^ 2 - 9x - 45 . A. (x - 5)(x ^ 2 + 9) b . (x - 5)(x - 3) * (x + 3) Factor By Groupin (x + 5)(x - 3) * (x +

jok3333 [9.3K]

Answer:

Step-by-step explanation:

Given

x³ + 5x² - 9x - 45 ( factor the first/second and third/fourth terms )

= x²(x + 5) - 9(x + 5) ← factor out (x + 5) from each term

= (x + 5)(x² - 9) ← factor as a difference of squares

= (x + 5)(x - 3)(x + 3)

3 0

3 years ago

Quadrilateral ABCD is similar to Quadrilateral EFGH. Diagonal AC has length 7 and diagonal EG has length 13. What is the scale f

olasank [31]

Answer:

$\large \boxed{\text{A. }\dfrac{13}{7}\text{; B. }\dfrac{17}{14} \text{; C. 507 in}^{2}}$

Step-by-step explanation:

A. Scale factor

When you dilate an object by a scale factor, you multiply its line lengths by the same number.

If EF/AB = 13/7, the scale factor is 13/7.

B. Length of EF

$\begin{array}{rcl}\dfrac{EF}{AB} & = & \dfrac{13}{7}\\\\\dfrac{EF}{\frac{17}{26}} & = & \dfrac{13}{7}\\\\EF & = & \dfrac{13}{7}\times\dfrac{17}{26}\\\\ & = &\dfrac{1}{7}\times\dfrac{17}{2}\\\\ & = & \mathbf{\dfrac{17}{14}}\\\end{array}\\\text{The length of EF is $\large \boxed{\mathbf{ \dfrac{17}{14}}}$}$

C. Area of EFGH

If the lengths in a shape are all multiplied by a scale factor, then the areas will be multiplied by the scale factor squared.

ABCD is dilated by a scale factor of 13/7, so its area is dilated by a scale factor of

$\left(\dfrac{13}{7} \right)^{2} = \dfrac{169}{49}$

The area of its dilated image EFGH is

$\text{Area of EFGH} = \text{147 in}^{2} \times \dfrac{\text{169}}{\text{49}} = 3 \times 169\text{ in}^{2} = 507 \text{ in}^{2}\\\\\text{The area of EFGH is $\large \boxed{\textbf{507 in}^{\mathbf{2}}}$}$

8 0

3 years ago