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Crank
3 years ago
15

Inferential statistics involves using population data to make inferences about a sample. Group of answer choices True False

Mathematics
1 answer:
zhuklara [117]3 years ago
8 0

Answer:

False. Is the inverse process.

See explanation below.

Step-by-step explanation:

We need to remember two important concepts:

A parameter, is a quantity or value who describe a population desired, for example the population mean \mu or the population standard deviation \sigma

A statistic, is a quantity or value who represent the information of the sample data, for example the sample mean \bar X or the sample deviation s

Based on this we can analyze the statement:

"Inferential statistics involves using population data to make inferences about a sample"

False. Is the inverse process.

If we know the population data then we indeed have parameters and we don't need to do any type of inference in order to estimate these parameters with the statistics.

What we do generally is use the information from the sample in order to obtain statistics representative of the population with the aim to estimate the parameters unknown of the population

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A park started with 12 oak trees, and the number of oak trees increased at a rate of 25% each year. Write the function that mode
Helen [10]

Answer:

The function which models the situation is as The number of oak trees increase after n year = 12 ×  (1+\frac{25}{100})^{n}

Step-by-step explanation:

Given as :

The number of oak trees planted in park = 12

The rate at which number of tree increase each year= 25%

Now,

The number of oak trees increase after n year = Present numbers of tree × (1+\frac{Rate}{100})^{n}

Or,

The number of oak trees increase after n year = 12 × (1+\frac{25}{100})^{n}

Hence The function which models the situation is as The number of oak trees increase after n year = 12 × (1+\frac{25}{100})^{n}  Answer

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3 years ago
A roulette wheel contains the integers 1 through 36, 0, and 00. suppose that you spin the wheel 6 times and that each time you b
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The probabability of winning on at least 1 bet is equal to 1 less the probaility of not winning on either of the 6 bets.

The probability of not wining on any bet is independent of winning or not winning on any of the bets, so the combined probability is calculated as the product of each individual probability.

Each indivitual probability of not winning the is:

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Then, the combined probability of not winning the six times is: (1/38)*(37/38)*(37/38)*(37/38)*(37/38)*(37/38) =(37/38)^6

Therefore, the probability of winning at least one bet is:

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Suppose it is known that the distribution of purchase amounts by customers entering a popular retail store is approximately norm
Ket [755]

Answer:

69.15% probability that a randomly selected customer spends less than $105 at this store

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 100, \sigma = 10

What is the probability that a randomly selected customer spends less than $105 at this store?

This is the pvalue of Z when X = 105. So

Z = \frac{X - \mu}{\sigma}

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69.15% probability that a randomly selected customer spends less than $105 at this store

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