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loris [4]
3 years ago
7

A reaction expected to produce 245.6 g of a product produces 122.1 g of the

Chemistry
1 answer:
slava [35]3 years ago
4 0

Answer:

50%

Explanation:

% yields =(experimental yields / theoretical yields ) x100%

            =    122.1÷  245.6 ) x100% = 50%

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How many electron are in the outer shell of an neutral atom of 14 atomic number
Anon25 [30]
I think there is 4 electrons in the outer shell of 14 atomic number. If I'm wrong, know that I'm not very good.
5 0
3 years ago
Hey, I’ll give brainliest. Just please help.
Andre45 [30]

Answer:

C

Explanation:

8 0
2 years ago
Write dissociation equations for the following soluble salts dissolving in water. Then draw a particle - level representation fo
zhuklara [117]

Answer:

The dissociation equations for NaBr gives Na+ and Br-

The dissociation equations for ZnCl2 gives Zn2+ and 2 Cl-  

Explanation:

The following pictures shows that the dissociation of one particle of NaBr produces one particle of Na+ (sodium cation) and one particle of Br- (bromine anion).

The dissociation of one particle of ZnCl2 produces one particle of Zn+2 (Zinc cation) and two particles of Cl- (chlorine anion).

8 0
3 years ago
Caffeine, a stimulant found in coffee, tea, and certain soft drinks, contains C, H, O, and N. Combustion of 1.000 mg of caffeine
Yuliya22 [10]

Answer:

  • <u>194 g/mol</u>

Explanation:

<u>1) Content of C:</u>

All the C atoms in the 1.000 mg of caffeine will be found in the 1.813 mg of CO₂.

  • Mass of C in 1.813 mg of CO₂

       Since the atomic mass of C is 12.01 g/mol and the molar of of CO₂ is 44.01, there are 12 mg of C in 44 mg of CO₂ and you can set the proporton:

       12.01 mg C / 44.01 mg CO₂ = x / 1.813 g CO₂

        ⇒ x = 1.813 × 12.01 / 44.01 g of C = 0.49475 mg of C

  • Number of moles of C

      number of moles = mass in g / atomic mass = 0.49475×10⁻³ g / 12.01 g/mol = 4.1195×10⁻⁵ moles = 0.041195 milimol

<u>2) Content of H</u>

All the H atoms in the 1.000 mg of caffeine will be found in the 0.4639 mg of H₂O

  • Mass of H in 0.4639 mg of H₂O

       Since the atomic mass of H is 1.008 g/mol and the molar of of H₂O is 18.015 g/mol, there are 2×1.008 mg of H in 18.015 mg of H₂O and you can set the proporton:

       2×1.008 mg H / 18.015 mg H₂O = x / 0.4639 mg H₂O

        ⇒ x = 0.4639 mg H₂O × 2 × 1.008 mg H / 18.015 mg H₂O = 0.051913 mg H

  • Number of moles of H

      number of moles = mass in g / atomic mass = 0.051913 ×10⁻³ g / 1.008 g/mol = 5.1501× 10⁻⁵ moles = 0.051501 milimol

<u>3) Content of N</u>

All the N atoms in the 1.000 mg of caffeine will be found in the 0.2885 mg of N₂

  • Mass of N in 0.2885 mg of N₂ is 0.2885 mg

  • Number of moles of N

      number of moles = mass in g / atomic mass = 0.2885 ×10⁻³ g / 14.007 g/mol = 2.0597× 10⁻⁵ moles = 0.020597 milimol

<u>4) Content of O</u>

The mass of O is calculated by difference:

  • Mass of O = mass of sample - mass of C - mass of H - mass of N

       Mass of O = 1.000 mg - 0.49475 mg C - 0.051913 mg H - 0.2885 mg N

     Mass of O = 0.1648 mg

  • Moles of O =  0.1648 × 10 ⁻³ g / 15.999 g/mol = 1.0303×10⁻⁵ mol = 0.01030 milimol

<u>5) Ratios</u>

Divide every number of mililmoles by the smallest number of milimoles:

  • C:  0.041195 / 0.01030 = 4
  • H: 0.051501 / 0.01030 = 5
  • N: 0.020597 / 0.01030 = 2
  • O: 0.01030 / 0.01030 = 1

  • C: 4
  • H: 5
  • N: 2
  • O: 1

<u>6) Empirical formula:</u>

  • C₄H₅N₂O₁

<u>7) Calculate the approximate mass of the empirical formula:</u>

  • 4 × 12 + 5 × 1 + 2 × 14 + 1 × 16 =  97 g/mol

So, since that number is not between 150 and 200 g/mol, multiply by 2: 97 × 2 = 194, which is between 150 and 200.

Thus, the estimate is 194 g/mol

7 0
3 years ago
How will temperature affect the spontaneity of a reaction with positive H and S?
BartSMP [9]

Answer:

D.A high temperature will make it spontaneous.

Explanation:

we know that

Δ G = Δ H - TΔS

For spontaneous reaction

Δ G should be negative . If Δ G = 0

Δ H =  TΔS

T =   Δ H / Δ S

At temperature above this T , Δ G becomes negative if Δ S and ΔH are  positive .

So at a  high temperature will make it spontaneous.

5 0
3 years ago
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