With the given formula, we can calculate the amount of CO₂ using the balance equation but we first need the moles of CH₄
1) to find the moles of CH₄, we need to use the ideal gas formula (PV= nRT). if we solve for n, we solve for the moles of CH₄, and then we can convert to CO₂. Remember that the units put in this formula depending on the R value units. I remember 0.0821 which means pressure (P) has to be in atm, volume (V) in liters, the amount (n) in moles, and temperature (T) in kelvin.
PV= nRT
P= 1.00 atm
V= 32.0 Liters
n= ?
R= 0.0821 atm L/mol K
T= 25 C= 298 K
let plug the values into the formula.
(1.00 x 32.0 L)= n x 0.0821 x 298K
n= (1.00 x 32.0 L )/ (0.0821 x 298)= 1.31 moles CH₄
2) now let's convert the mole of CH₄ to moles to CO₂ using the balance equation
1.31 mol CH₄ (1 mol CO₂/ 1 mol CH₄)= 1.31 mol CO₂
3) Now let's convert from moles to grams using the molar mass of CO₂ (find the mass of each atom in the periodic table and add them)
molar mass CO₂= 12.00 + (2 x 16.0)= 44.0 g/mol
1.31 mol CO₂ ( 44.0 g/ 1 mol)= 57.6 g CO₂
Note: let me know if you any question.
Answer:
Explanation:
The balanced chemical equation is:
Now, standard values of 
Now, We know 
Putting all values of 
to above equation.
We get,
Hence, this is the required solution.
First row: HCl, ZnCl2, FeCl3, AlCl3, BaCl2, PbCl4
Second row: H3P, Zn3P2, FeP, AlP, Ba3P2, Pb3P4
Third row: HNO3, Zn(NO3)2, Fe(NO3)3, Al(NO3)3, Ba(NO3)2, Pb(NO3)4
Fourth row: ZnO, Fe2O3, Al2O3, BaO, PbO2
Fifth row: HCaF2, Zn(CaF2)2, Fe(CaF2)3, Al(CaF2)3, Ba(CaF2)2, Pb(CaF2)4
Sixth row: H2SO4, ZnSO4, Fe2(SO4)3, Al2(SO4)3, BaSO4, Pb(SO4)2
