Answer:
D metallic
Explanation:
The chemical bonding which rises from electrostatic attractive force between the conduction electrons and the positively charged metal ions is called metallic bonding.
<u>It is sharing of the free electrons among the structure of the positively charged ions which are known as cations.
</u>
<u>In this type of bonding, these free electrons freely move in the crystal mattice of the metal. </u>
The bonding accounts for properties of metals, such as ductility, strength, electrical and thermal conductivity and resistivity and luster.
<span>The ideal gas law.
PV=nRT
pressure x volume = moles x Faraday's constant x Temp Kelvin (C+273)
Original data
Pressure 1 atmosphere
Volume 1 liter
Temp 25C = 298K
New data
Volume 0.5 liter
pressure X
Temp 260C = 533K
P1v1T1 = P2v2T2
plug and chug.
(1)(1)(293) = (x)(0.5)(533)
Solve for X, which is the new pressure. </span>
Answer:
The answer is 465.6 mg of MgI₂ to be added.
Explanation:
We find the mole of ion I⁻ in the final solution
C = n/V -> n = C x V = 0.2577 (L) x 0.1 (mol/L) = 0.02577 mol
But in the initial solution, there was 0.087 M KI, which can be converted into mole same as above calculation, equal to 0.02242 mol.
So we need to add an addition amount of 0.02577 - 0.02242 = 0.00335 mol of I⁻. But each molecule of MgI₂ yields two ions of I⁻, so we need to divide 0.00335 by 2 to find the mole of MgI₂, which then is 0.001675 mol.
Hence, the weight of MgI₂ must be added is
Weight of MgI₂ = 0.001675 mol x 278 g/mol = 0.4656 g = 465.6 mg
Answer:
Compound B and D
Explanation:
Both are good conductors of electricity.
The factor that does not influence stream velocity is DISCHARGE.
Stream velocity refers to the speed with which the water in a stream is flowing. The factors which affect stream velocity include channel size, channel shape, turbulent flow and gradient.
