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jeka94
4 years ago
7

How many atoms are in CeCL3

Chemistry
2 answers:
SOVA2 [1]4 years ago
7 0
Molar mass of CeCl3 = 246.475 g/mol

This compound is also known as Cerium(III) Chloride.

Convert grams CeCl3 to moles or moles CeCl3 to grams

Molecular weight calculation:
140.116 + 35.453*3
kicyunya [14]4 years ago
3 0

Chlorine Cl 35.453 atomic mass 3 atoms Mass percent: 43.152%

Cerium Ce 140.116 atomic mass 1 atom Mass Percent: 56.848%

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I need help FAST ASAP
kiruha [24]
In this item, we are simply to find the ions that may bond and are able to form a formula unit. We are also instructed to give out their name. There are numerous possible combinations of ions to form a compound. Some answers are given in the list below.

1.  Na⁺     ,    Cl⁻    , NaCl   ---> sodium chloride (this is most commonly known as table salt)

2. C⁴⁺       , O²⁻     , CO₂  ---> carbon dioxide

3. Al³+     , Cl⁻       , AlCl₃   ----> aluminum chloride

4. Ca²⁺     , Cl⁻     , CaCl₂    ---> calcium chloride

5. Li⁺        , Br⁻      , LiBr       ---> lithium bromide

6. Mg³⁺     , O²⁻      , Mg₂O₃   ----> magnesium oxide

7. K⁺        , I⁻          , KI   ---> potassium iodide

8. H⁺        , Cl⁻        , HCl  --> hydrogen chloride

9. H⁺        , Br⁻         , HBr ----> hydrogen bromide

10. Na⁺    , Br⁻         , NaBr   ---> sodium bromide
6 0
4 years ago
A 62.6-gram piece of heated limestone is placed into 75.0 grams of water at 23.1°C. The limestone and the water come to a final
VMariaS [17]
M₁ = mass of water = 75 g
T₁ = initial temperature of water = 23.1 °C
c₁ = specific heat of water = 4.186 J/g°C

m₂ = mass of limestone = 62.6 g
T₂ = initial temperature of limestone = ?
c₂ = specific heat of limestone = 0.921 J/g°C

T = equilibrium temperature = 51.9 °C
using conservation of heat
Heat lost by limestone = heat gained by water
m₂c₂(T₂ - T) = m₁c₁(T - T₁)
inserting the values
(62.6) (0.921) (T₂ - 51.9) = (75) (4.186) (51.9 - 23.1)
T₂ = 208.73 °C
in three significant figures
T₂ = 209 °C
7 0
4 years ago
2 NaOH (s) + CO2(g) → Na2CO3 (s) + H20 (I) How many grams of water can be produced with 1.85 moles of NaOH​
Romashka [77]

Explanation:

Mole ratio of NaOH to H2O = 2 : 1

Moles of H2O = 1.85mol * (1/2) = 0.925mol.

Mass of H2O = 0.925mol * (18g/mol) = 16.65g.

4 0
3 years ago
Read 2 more answers
if 3.56 moles of HCI reacts with excess Mg(OH)2. how many miles of mgcl2 will be produced, and how many moles of h2o are produce
zmey [24]

Answer:

 H₂O = 3.56 moles

 MgCl₂ = 1.78 moles

Explanation:

Given data:

Moles of HCl = 3.56 mol

Moles of water produced = ?

Moles of MgCl₂ produced = ?

Solution:

Chemical equation:

2HCl + Mg(OH)₂   →  MgCl₂ + 2H₂O

Now we will compare the moles of HCl with water and magnesium chloride.

                         HCl       :        MgCl₂

                            2        :           1

                           3.56    :          1/2×3.56 = 1.78 mol

                         HCl       :          H₂O

                            2        :           2

                           3.56    :          3.56 mol

8 0
3 years ago
5 points
agasfer [191]
Answer :
I think is A
5 0
3 years ago
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