The law of motion that states than an object will maintain its straight-line motion until acted upon by an unbalanced force is

Suppose you hit a steel nail with a 0.500-kg hammer, initially moving at 15.0 m/s and brought to rest in 2.80 mm. How much is th

katrin [286]

Complete Question

Suppose you hit a steel nail with a 0.500-kg hammer, initially moving at 15.0 m/s and brought to rest in 2.80 mm. How much is the nail compressed if it is 2.50 mm in diameter and 6.00-cm long.What Average force is excreted on the Nail

Answer:

$F=2*10^{4}N$

Explanation:

From the question we are told that:

Mass $m=0.500kg$

Initial Velocity $V=15.0m/s$

Distance $x=2.80mm=>0.00280m$

Diameter $d=2.50mm=>0.00250m$

Length $l=6.00cm=>0.6m$

Generally the equation for Force is mathematically given by

$F=\frac{mv^2}{2d}$

$F=\frac{0.500*15^2}{2.80*10^{-3}}$

$F=2*10^{4}N$

6 0

3 years ago

An element with 7 valence electrons will most likely-

Vladimir79 [104]

Answer: be found in group 17 and be highly reactive

Explanation:

Elements are distributed in groups and periods in a periodic table.

Elements that belong to same groups will show similar chemical properties because they have same number of valence electrons.

Flourine, chlorine, bromine and iodine are elements which belong to Group 17. All of them contain 7 valence electrons each and need one electron to complete their octet.

The chemical reactivity of elements is governed by the valence electrons present in the element and thus all of them are highly reactive.

3 0

4 years ago

25% part (c) assume that d is the distance the cheetah is away from the gazelle when it reaches full speed. Derive an expression

levacccp [35]

maximum speed of cheetah is

$v_1 = v_{max}$

speed of gazelle is given as

$v_2 = v_{g}$

Now the relative speed of Cheetah with respect to Gazelle

$v_{12} = v_1 - v_2$

$v_{12} = v_{max} - v_g$

now the relative distance between Cheetah and Gazelle is given initially as "d"

now the time taken by Cheetah to catch the Gazelle is given as

$d = v_{12}* t$

so by rearranging the terms we can say

$t = \frac{d}{v_{12}}$

$t = \frac{d}{v_{max} - v_g}$

so above is the relation between all given variable

6 0

4 years ago

Sound waves are longitudinal waves that can travel through air. Would you expect sound waves to travel faster through a low-dens

Serjik [45]

Answer:

Sound waves travel faster in a low-density gas

Explanation:

First of all, let's remind that sound waves are pressure waves: they consist of oscillations of the particles in a medium, which oscillate back and forth along the direction of motion of the wave (longitudinal wave).

The speed of sound in an ideal gas is given by the equation

$v=\sqrt{\gamma \frac{p}{\rho}}$

where

$\gamma$ is the adiabatic index of the gas

p is the gas pressure

$\rho$ is the gas density

From the equation, we see that the speed of sound is inversely proportional to the square root of the density: therefore, the lower the density, the faster the sound waves.

So, sound waves will travel faster in a low-density gas.

6 0

3 years ago

An FM radio consists of a series RLC circuit with a 6.57 pF (peco – 10-12) capacitor. If a person is dialed into a station broad

faust18 [17]

Answer:

3.6 x 10⁻⁷ H

Explanation:

C = capacitance of the capacitor = 6.57 x 10⁻¹² F

L = inductance of the inductor = ?

f = frequency of broadcasting system = 103.9 MHz = 103.9 x 10⁶ Hz

frequency is given as

$f = \frac{1}{2\pi \sqrt{LC}}$

$103.6\times 10^{6} = \frac{1}{2(3.14)\sqrt{(6.57\times 10^{-12})L}}$

Inserting the values

L = 3.6 x 10⁻⁷ H

4 0

3 years ago