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Kisachek [45]
3 years ago
15

A cyclist rides 3 km west and then turns around and rides 2 km east. What is her displacement?

Physics
1 answer:
geniusboy [140]3 years ago
5 0

Answer:

1km west

Explanation:

Because if the cyclist is going back 2km then its 3-2=1km

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dimaraw [331]

CO₃

Explanation:

The polyatomic ion in the compound CaCO₃ is CO₃.

A polyatomic ion is an ion that is made up of more than one atom that has singular property.

They are usually called radicals.

    CaCO₃ ⇒  Ca²⁺  + CO₃²⁻

CO₃²⁻ is a polyatomic ion because it is made up of more than one atom.

The CO₃²⁻ is called a carbonate group.

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learn more:

Polyatomic ions brainly.com/question/6786947

#learnwithBrainly

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(ii) two locomotives approach each other on parallel tracks. each has a speed of 155 km/h with respect to the ground. if they ar
IgorLugansk [536]
You have to find an equation that would relate the two motions of the locomotives. When they meet at a certain point after being 8.5 km apart initially, then that means that their individual distances traveled is equal to 8.5 The solution is as follows:

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4 0
4 years ago
Do you agree or disagree that folk dance forms can be outside their original formmeaningful s
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I disagree that folk dance forms can be outside their original meaningful form in this scenario.

<h3>What is Folk dance?</h3>

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This dance is a ritualistic entertainment which is done in different type of gatherings such as ceremonies etc which is why it isn't outside their original meaningful form.

Read more about Folk dance here brainly.com/question/18269425

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How would a person who believes in the geocentric solar
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3 years ago
PLEASEEEE HEEEEELP!!!!!
8090 [49]

Answer:

Before:

p_{truck}=16400\ kg.m/s

p_{car}=10000\ kg.m/s

After:

p_{truck}=8000\ kg.m/s

p_{car}=8400\ kg.m/s

v_{fcar}=8.4\ m/s

F=9333.33 \ Nw

Explanation:

<u>Conservation of Momentum</u>

Two objects of masses m1 and m2 moving at speeds v1o and v2o respectively have a total momentum of

p_1=m_1v_{1o}+m_2v_{2o}

After the collision, they have speeds of v1f and v2f and the total momentum is

p_2=m_1v_{1f}+m_2v_{2f}

Impulse J is defined as

J=F.t

Where F is the average impact force and t is the time it lasted

Also, the impulse is equal to the change of momentum

J=\Delta p

As the total momentum is conserved:

p_1=p_2

m_1v_{1o}+m_2v_{2o}=m_1v_{1f}+m_2v_{2f}

We can compute the speed of the second object by solving the above equation for v2f

\displaystyle v_{2f}=\frac{ m_1v_{1o}+m_2v_{2o} -m_1v_{1f} }{  m_2 }

The given data is

m_1=2000\ kg

m_2=1000\ kg\\v_{1o}=8.2\ m/s\\v_{2o}=0\ m/s\\v_{1f}=4\ m/s

a) The impulse will be computed at the very end of the answer

b) Before the collision

p_{truck}=2000\cdot 8.2=16400\ kg.m/s

p_{car}=1000\cdot 0=0\ kg.m/s

c) After collision

p_{truck}=2000\cdot 4=8000\ kg.m/s

Compute the car's speed:

\displaystyle v_{2f}=\frac{ 16400+0 -8000 }{ 1000 }

v_{2f}=8.4\ m/s

And the car's momentum is

p_{car}=1000\cdot 8.4=8400\ kg.m/s

The Impulse J of the system is zero because the total momentum is conserved, i.e. \Delta p=0.

We can compute the impulse for each object

J_1=\Delta p_1=2000(4-8.2)=-8400 \N.s

The force can be computed as

\displaystyle F=\frac{J}{t}=-\frac{8400}{0.9}=-9333.33 \ Nw

The force on the car has the same magnitude and opposite sign

7 0
4 years ago
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