Answer:
The surface area of right regular hexagonal pyramid = 82.222 cm³
Step-by-step explanation:
Given as , for regular hexagonal pyramid :
The of base side = 3 cm
The slant heights = 6 cm
Now ,
The surface area of right regular hexagonal pyramid = 
Where a is the base side
And h is the slant height
So, The surface area of right regular hexagonal pyramid = 
Or, The surface area of right regular hexagonal pyramid = 
Or, The surface area of right regular hexagonal pyramid = 23.38 + 9 × 
∴ The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538
I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842
So, The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer
For every 3 you go across you go up 1 so the gradient is rise/run = 1/3
Therefore gradient is 1/3
Answer:
D
Step-by-step explanation:
379.00 - 15.00 + 154.00 x 3 + 65.00 + 13.00 = 904
0.55 x 63 = 34.65
34.65 + 904 = 938.65
Answer:
Part 1) The vertex is the point (-83,-9)
Part 2) The focus is the point (-82.75,-9)
Part 3) The directrix is 
Step-by-step explanation:
step 1
Find the vertex
we know that
The equation of a horizontal parabola in the standard form is equal to
where
p≠ 0.
(h,k) is the vertex
(h + p, k) is the focus
x=h-p is the directrix
In this problem we have
Convert to standard form
so
This is a horizontal parabola open to the right
(h,k) is the point (-83,-9)
so
The vertex is the point (-83,-9)
step 2
we have
<em>Find the value of p</em>
<em>Find the focus</em>
(h + p, k) is the focus
substitute
(-83+1/4,-9)
The focus is the point (-82.75,-9)
step 3
Find the directrix
The directrix of a horizontal parabola is
substitute
First put 54 over X in a fraction. 54/x
<span>Then put 75 over 100. 75/100 </span>
<span>Then you cross multiply. 75(x)= 54(100) </span>
<span>Simplify. 75x = 5400 </span>
<span>Divide. x=72 </span>
<span>Your answer is 72
</span>
