First you need to use the distributive property: 27(x+4)=-6
27x+108=-6
then you need to subtract 108 from -6 to
get x alone. 27x= 102
Lastly divide 102 by 27 to finally get x alone: x=3.777
the answer would be: x= 3.77 or 3.8
If you would like to solve the equation b^2 + 9 * b + 18 = 0 for the variable b, you can do this using the following step:
b^2 + 9 * b + 18 = 0
(b + 3) * (b + 6) = 0
Result:
1. solution: b = - 3
2. solution: b = - 6
Answer:
A - 0%
B- 50%
C- 50%
D- 100%
Step-by-step explanation:
Cystic fibrosis is inherited in an autosomal recessive form, meaning that a person has to inherit two abnormal genes for the disease to manifest. In the case of this question, one parent is a gene carrier, so his genotype is Aa, while the other does not have the cystic fibrosis gene, so AA.
Performing the cross of Aa x AA, we can see that:
a.) The probability of a child would have cystic fibrosis is 0%, since the disease is recessive and to be affected it should receive a recessive gene from each parent.
b.) The probability of a child would be a carrier is 50%, as 50% of the crossing phenotypes are Aa.
c.) The probability of a child would not have cystic fibrosis and is not a carrier is 50%, as 50% of the child's genotype is AA.
d.) The probability of a child would be healthy is 100%, as of all possible phenotypes none is affected.
Answer:
Step-by-step explanation:
ohhh this is easyyy its
