The reaction that represents the half-reaction of lead Pb is
Pb2+(aq) + 2e- → Pb(s)
and the SRP value on electric potential table is -0.13V.
To find the overall potential of a reaction, two half reactions can be added
together:
Oxidation: Fe(s) → Fe2+(aq) + 2e- +0.44V
Reduction: Pb2+(aq) + 2e- → Pb(s) - 0.13 V
Overall reaction: Fe(s) + Pb2+(aq) → Pb(s) + Fe2+(aq) +0.31V
This positive voltage for the overall reaction is spontaneous.
2................ 2................ 2................
Answer:
methane + oxygen → carbon dioxide + water
Explanation:
methane + oxygen → carbon dioxide + water
Following reaction is involved in above system
HOCl(aq) ↔ H+(aq) + OCl-<span>(aq)
</span>OCl-(aq) + H2O(l) ↔ HOCl(aq) + OH-<span>(aq)
</span>
Now, if the system is obeys 1st order kinetics we have
K = [OCl-][H+<span>]/[HOCl] ............. (1)
</span>∴ [HOCl-] / [OCl-] = [H+] (1 / 3.0 * 10-8<span>) ............. (2)
</span>
and now considering that system is obeying 2nd order kinetics, we have
K = [OH-][HOCl-] / [OCl-] ................. (3<span>)
</span>Subs 2 in 3 we get
K = [OH-][H+] (1 / 3.0 * 10-8<span>)
</span>we know that, [OH-][H+] = 10<span>-14
</span>∴K = 3.3 * 10<span>-7
</span>
Thus, correct answer is e i.e none of these
Answer:
Organic compound, any of a large class of chemical compounds in which one or more atoms of carbon are covalently linked to atoms of other elements, most commonly hydrogen, oxygen, or nitrogen.
