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4 years ago

Which of the following compounds has the highest boiling point?

Chemistry

2 answers:

jenyasd209 [6]4 years ago

8 0

Answer: chloropentane

Explanation:

When a hydrocarbon has a halogen atom, its properties will change because this group has a higher molecular weight and a higher polar moment that will be hard to defeat in order to reach the boiling point.

The Boiling point of the pentene is 30°C // pentane is 36,1°C // 2-pentanone is 101°C and chloropentane 108°C.

Simple hydrocarbons have lower boiling points compare with those with a functional group like the Oxygen in the 2-pentanone and the Chlorine in the chloropentane. On the other heand, Oxygen is not as electronegative and heavy like Chlorine, thus the chloropentane is the one with higher boiling point.

marta [7]4 years ago

3 0

The answer is chloropentane

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Cell potential =∈° red - ∈° oxidation

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3 years ago

At a certain temperature a 42.55% (v/v) solution of ethyl alcohol, C2H5OH, in water has a density of 0.9027 g mL-1. The density

swat32

Answer:

a. 7.187M.

b. 7.962m.

c. 0.1846

Explanation:

This solution contains 42.55mL of ethyl alcohol in 100mL of solution.

a. Molar concentration = Moles ethyl alcohol / L solution:

Moles ethyl alcohol -Molar mass: 46.07g/mol-

42.55mL * (0.7782g/mL) * (1mol / 46.07g) = 0.7187 moles ethyl alcohol

Liters solution:

100mL * (1L / 100mL) = 0.100L

Molar concentration: 0.7187mol / 0.100L = 7.187M

b. Molal concentration: Moles ethyl alcohol (0.7187moles) / kg solution

kg solution:

100mL * (0.9027g / mL) * (1kg / 1000g) = 0.09027kg

Molal concentration: 0.7187mol / 0.09027kg = 7.962m

c. Mole fraction: Moles ethyl alcohol / Moles ethyl alcohol + moles water

Moles water: -molar mass: 18.01g/mol-

Volume water = 100mL - 42.55mL = 57.45mL

57.45mL * (0.9949g/mL) * (1mol/18.01g) = 3.1736 moles water

Moles fraction:

0.7187 moles ethyl alcohol / 0.7187 moles ethyl alcohol+3.1736 moles water

= 0.1846

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