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kotegsom [21]
3 years ago
12

How to do the fractions

Mathematics
1 answer:
Alenkasestr [34]3 years ago
3 0

you could either multiply straight away or you could simplify right then so that you wouldn't have to it later.

20/5 * 5/2

your answer would be 10 either way

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Write the fractions as fractions with a common denominator 3/4 and 1/3
JulijaS [17]

3/4 and 1/3

4x3 = 12 that will be the common denominator.

For 3/4 we first divide 12/4 = 3 and then multiply 3 x3 = 9 that's the numerator

For 1/3 we first divide 12/3 = 4 and then multiply 1x4 = 4 that's the numerator

The fractions will be rewrited as: 9/12 and 4/12

3 0
1 year ago
Consider two competing firms in a declining industry that cannot support both firms profitably. Each firm has three possible cho
yaroslaw [1]

Answer:

a) attached below

b)  ( T,T )

c) The Pure-strategy Nash equilibria are : ( N,E ) and ( E,N )

d) The mixed-strategy Nash equilibrium for Firm 1 = ( 1/3 , 0, 2/3 )

while the mixed -strategy Nash equilibrium for Firm 2 = ( 1/3 , 0, 2/3 )

Step-by-step explanation:

A) write down the game in matrix form

let: E = exit at the industry immediately

     T = exit at the end of the quarter

     N = exit at the end of the next quarter

matrix is attached below

B) weakly dominated strategies is ( T,T )

C) Find the pure-strategy Nash equilibria

The Pure-strategy Nash equilibria are : ( N,E ) and ( E,N )

D ) Find the unique mixed-strategy Nash equilibrium

The mixed-strategy Nash equilibrium for Firm 1 = ( 1/3 , 0, 2/3 )

while the mixed -strategy Nash equilibrium for Firm 2 = ( 1/3 , 0, 2/3 ) since T is weakly dominated then the mixed strategy will be NE

Assume that P is the probability of firm 1 exiting immediately ( E )

and q is the probability of firm 1 staying till next term ( N ) ∴ q = 1 - P.

hence the expected utility of firm 2 choosing E = 0 while the expected utility of choosing N = 4p - 2q .

The expected utilities of E and N to firm 2 =

0 = 4p - 2q = 4p - 2 ( 1-p) = 6p -2 which means : p = 1/3 , q = 2/3

4 0
2 years ago
Please help me with this question!
gavmur [86]
First off, let's convert the percentages to decimal format, so our 77% turns to 77/100 or 0.77, and our 55% turns to 55/100 or 0.55 and so on

now, the sum of both salines, must add up to the 77% mixture, let's say is "y"
so, 11 + 4 = y, and whatever the concentration level is, must also sum up to the mixture's concentration of 77%

anyway   thus

\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{first sol'n}&11&x&11x\\
\textit{second sol'n}&4&0.55&2.20\\
------&-----&-------&-------\\
mixture&y&0.77&0.77y
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
11+4=y\implies 15=\boxed{y}\\
11x+2.2=0.77y\\
----------\\
11x+2.2=0.77\cdot \boxed{15}
\end{cases}

solve for "x"
6 0
3 years ago
Which set represents the range of the function shown?<br> {(8, 2), (6, 5), (4, 7), (11, −2)}
kakasveta [241]
The second numbers in each of the ordered pairs is the range
3 0
3 years ago
Find the value of x in each of the following<br>a) 5x/2+ 1 = 11<br>b) 2x/7 – 3 = 2​
laila [671]

Answer:

A) x=4

B) x=35/2

Step-by-step explanation:

calculate the product

A) 5x/2+1=11

multiply both sides of the equation by 2

5x+2=22

move the constant to the right hand side and change its sign

5x+22-2

now subtract the numbers

5x=20

now didvide both sides

5x=20

x=4

B)

calculate the product

2x/7-3=2

multiply both sides of the equation by 7

2x-21=14

move the constant to the right hand side and change its sign

2x=14+21

add the numbers

2x=35

now divide both sides of the equation by 2

x=35/2

8 0
3 years ago
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