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3 years ago

Operations absolute value |4 - 9| =|4| -9 =

Mathematics

1 answer:

Lelu [443]3 years ago

6 0

|4-9|
|-5|
5

|4|-9
4-9
-5

absolute value is the numbers distance from zero

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Can you make all the numbers from 1 to 20 using 4 fours?

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Answer: no you can't you can only use 5 numbers when going by 4's

Step-by-step explanation: 4, 8, 12, 16, 20

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3 years ago

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last week a share of stock gained a total of 1.64 points express this gain as a mixed number in simplest form

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Answer:

1 16/25

Step-by-step explanation:

1 whole and remaining decimal 0.64

0.64 is 64/100 as a fraction which simplifies to 16/25

So as a whole number its 1 + 16/25 which is 1 16/25

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3 years ago

What would be the measure of angle J?

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3 years ago

Solve each pair of simulation equation.Giving both solutions. Multiply both equations by suitable numbers before adding/subtract

pashok25 [27]

Answer:

Step-by-step explanation:

I haven't got time to do all these by I'll give you the method in each case.

You have to make the x or y term equal (or 1 term + and other -) in both equations before adding or subtracting.

A . Multiply equation 2 by 2 and subtract (to eliminate x)

- don't forget to multiply EACH TERM by 2.

B. Multiply equation 2 by -2 and add.

C. Multiply equation 1 by 3 and equation 2 by 2 ( this will give -6y and +6y in the resulting equations ) so you then add to eliminate y.

D. Multiply equation 1 by 13 and equation and equation 2 by 2 to eliminate x then add.

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2 years ago

Match the following rational expressions to their rewritten forms.

Nookie1986 [14]

Answer:

Answer image is attached.

Step-by-step explanation:

Given rational expressions:

$1.\ \dfrac{x^2+x+4}{x-2}\\2.\ \dfrac{x^2-x+4}{x-2}\\3.\ \dfrac{x^2-4x+10}{x-2}\\4.\ \dfrac{x^2-5x+16}{x-2}$

And the rewritten forms:

$(x-2)+\dfrac{6}{x-2}\\(x+3)+\dfrac{10}{x-2}\\(x+1)+\dfrac{6}{x-2}\\(x-3)+\dfrac{10}{x-2}$

We have to match the rewritten terms with the given expressions.

Let us consider the rewritten terms and let us solve them one by one by taking LCM.

$(x-2)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x-2)^{2}+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+4+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+10}{x-2}$

So, correct option is 3.

$(x+3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x+3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{(x^2+3x-2x-6)+10}{x-2}\\\Rightarrow \dfrac{x^2+x+4}{x-2}$

So, correct option is 1.

$(x+1)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x+1)(x-2)+6}{x-2}\\\Rightarrow \dfrac{x^{2} +x-2x-2+6}{x-2}\\\Rightarrow \dfrac{x^{2} -x+4}{x-2}$

So, correct option is 2.

$(x-3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x-3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{x^2-3x-2x+6+10}{x-2}\\\Rightarrow \dfrac{x^2-5x+16}{x-2}$

So, correct option is 4.

The answer is also attached in the answer area.

7 0

3 years ago