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3 years ago

Help plz correct answer get brainliest

Mathematics

1 answer:

Elina [12.6K]3 years ago

6 0

No it is a straight line they are not collinear

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The midpoint of AB is M(-5,1). If the coordinates of A are (-4,-5), what are the coordinates of B?

Elenna [48]

<u>ANSWER:</u>

The midpoint of AB is M(-5,1). The coordinates of B are (-6, 7)

<u>SOLUTION: </u>

Given, the midpoint of AB is M(-5,1).

The coordinates of A are (-4,-5),

We need to find the coordinates of B.

We know that, mid-point formula for two points A $(x_{1}, y_{1})$ and B $(x_{1}, y_{2})$ is given by

$M\left(x_{3}, y_{3}\right)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

Here, in our problem, $\mathrm{x}_{3}=-5, \mathrm{y}_{3}=1, \mathrm{x}_{1}=-4 \text { and } \mathrm{y}_{1}=-5$

Now, on substituting values in midpoint formula, we get

$(-5,1)=\left(\frac{-4+x_{2}}{2}, \frac{-5+y_{2}}{2}\right)$

On comparing, with the formula,

$\frac{-4+x_{2}}{2}=-5 \text { and } \frac{-5+y_{2}}{2}=1$

$-4+\mathrm{x}_{2}=-10 \text { and }-5+\mathrm{y}_{2}=2$

$\mathrm{x}_{2}=-6 \text { and } \mathrm{y}_{2}=7$

Hence, the coordinates of b are (-6, 7).

5 0

3 years ago

Analyzing Graphs of Functions<br> Which graph shows a function where f(2) = 4?

professor190 [17]

Answer:

the first one

Step-by-step explanation:

check which graph passes through the point (2,4)

6 0

2 years ago

The temperature fell by 15 degrees Fahrenheit today.

katrin2010 [14]

<h3>Answer is -15</h3>

We read this out as "negative 15" or you could write "negative fifteen".

The negative indicates the temperature went down. It doesn't necessarily mean that the final temperature is -15 degrees.

For example, if it starts being 50 degrees F, and drops by 15 degrees, then 50+(-15) = 50-15 = 35 degrees is the temperature after that drop. It might help to use a vertical number line.

8 0

3 years ago

Ima need sum more help

laiz [17]

Answer:

Step-by-step explanation:

Because yes

4 0

3 years ago

Read 2 more answers

Tan + Cos / 1 + Sin = Sec

yaroslaw [1]

$\tan x+\frac{\cos x}{1+\sin x}\\\\ =\frac{\sin x}{\cos x}+\frac{\cos x}{1+\sin x}\\\\=\frac{\sin x(1+\sin x)+\cos^{2} x}{\cos x(1+\sin x)}\\\\=\frac{\sin^{2} x+\cos^{2} x+\sin x}{\cos x(1+\sin x)}\\\\=\frac{1+\sin x}{\cos x(1+\sin x)}\\\\=\frac{1}{\cos x}\\\\=\sec x$

7 0

1 year ago