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4 years ago

Describe the benefits of having an operational data warehouse (DWH), and the challenges of operating a DWH repository.

Computers and Technology

1 answer:

kvasek [131]4 years ago

5 0

Answer:

The benefits of having the operational data ware-house are as follows:

The single operational warehouse typically support various tactical and the strategical decisions.
It is subject oriented,volatile and integrated data warehousing in the system.
The warehousing mainly allow the system to process the large complex data in more efficient manner.
The operational warehouse are basically implemented for many business purposes.

The challenges of the operational warehouse repository are as follows:

In the operational data warehouse there is large number of user expectations.
The cost is the main challenge while designing the operational data warehousing as, it required efficient system in low cost.
Choosing the efficient and correct type of the warehouse is the big challenge.

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An important task that the operating system performs is ____, which keeps track of the files stored on a computer so that they c

finlep [7]

#1) An important task that the operating system performs is ____, which keeps track of the files stored on a computer so that they can be retrieved when needed.
Answer: File Management System. Keeps track of where files are stored and determines how the files are stored following the operating system file allocation policies. It uses available storage space efficiently for files and creates a record/log of all file usage. It allocates a file to a user if is free, and if they are permitted access to it. Then de-allocates file when the user is finished with it.

8 0

3 years ago

Write a Java program that prompts the user to enter integer values for the sides of a triangle and then displays the values and

satela [25.4K]

Answer:

import java.util.Scanner;

public class triangle {

public static void main (String [] args) {

int sideOne, sideTwo, sideThree;

Scanner in = new Scanner (System.in);

System.out.println("Enter the first side of the triangle");

sideOne = in.nextInt();

System.out.println("Enter the secon side of the triangle");

sideTwo = in.nextInt();

System.out.println("Enter the third side of the triangle");

sideThree = in.nextInt();

if ( sideOne<=0||sideTwo<=0|| sideThree<=0){

System.out.println(" The Values enter are "+sideOne+ "," +sideThree+ ","+sideThree+ " These values don't make a valid triangle");

}

else if ((sideOne + sideTwo> sideThree) || (sideOne+sideThree > sideTwo) || (sideThree+sideTwo > sideOne))

{

System.out.println ("The triangle is Valid");

}

else {

System.out.println(" The Values enter are "+sideOne+ "," +sideTwo+ ","+sideThree+ " These values don't make a valid triangle");

}

Explanation:

for a Triangle to be Valid one of the three sides of the triangle must greater than the other two sides. The code above enforces this condition using an if statement in combination with the Or Operator

The following conditions where enforced

side one, side two and side three != 0

Side One + Side Three > Side Two

Side Three + Side Two> Side One

Side Two + Side One > Side Three

7 0

3 years ago

HEYY GUYS START REPORTING ALL THE SPAMMERS PLSS!!!!! For the spammers, I hope you go to hell >:c!!!!!!!!!!!

Molodets [167]

Answer:

i totally agree

Explanation:

4 0

3 years ago

Find the root using bisection method with initials 1 and 2 for function 0.005(e^(2x))cos(x) in matlab and error 1e-10?

frutty [35]

Answer:

The root is:

$c=1.5708$

Explanation:

Use this script in Matlab:

-------------------------------------------------------------------------------------

function [c, err, yc] = bisect (f, a, b, delta)

% f the function introduce as n anonymous function

% - a y b are the initial and the final value respectively

% - delta is the tolerance or error.

% - c is the root

% - yc = f(c)

% - err is the stimated error for c

ya = feval(f, a);

yb = feval(f, b);

if ya*yb > 0, return, end

max1 = 1 + round((log(b-a) - log(delta)) / log(2));

for k = 1:max1

c = (a + b) / 2;

yc = feval(f, c);

if yc == 0

a = c;

b = c;

elseif yb*yc > 0

b = c;

yb = yc;

else

a = c;

ya = yc;

end

if b-a < delta, break, end

end

c = (a + b) / 2;

err = abs(b - a);

yc = feval(f, c);

-------------------------------------------------------------------------------------

Enter the function in matlab like this:

f= @(x) 0.005*(exp(2*x)*cos(x))

You should get this result:

f =

function_handle with value:

@(x)0.005*(exp(2*x)*cos(x))

Now run the code like this:

[c, err, yc] = bisect (f, 1, 2, 1e-10)

You should get this result:

c =

1.5708

err =

5.8208e-11

yc =

-3.0708e-12

In addition, you can use the plot function to verify your results:

fplot(f,[1,2])

grid on

5 0

3 years ago

A _____ system allows a customer to request a fax using email, via the company website, or by telephone.

balu736 [363]

A faxback system allows a customer to request a fax using email, via the company website, or by telephone.

<h3>What is faxback?</h3>

Faxback (usually uncountable, plural faxback) An interactive electronic service permitting documents to be downloaded via fax machine. FaxBack searches a pre-assigned database to validate numerals provided while at the same time recovering a caller's name and fax number. Callers without an account can hear a message in- structing them on how to receive an account or be given the option of furnishing a credit card.

FaxBack Fax Machine Solutions add features to the fax machine equivalent to how VoIP added components to the phone: receive fax notification via email and track, archive, and manage faxes via the fax server or service provider control panel.

Hence, A faxback system allows a customer to request a fax using email, via the company website, or by telephone.

To learn more about faxback refer to:

brainly.com/question/13735750

#SPJ4

4 0

1 year ago