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SEISMOGRAM
The atom contains three kinds of particles:
- <u>Electrons</u>: They are negative charged particles with charge of 1.6×
C and they spin around the nucleus in specific orbits - <u>Protons</u>: They are positive charged particles with the same charge of the electrons (but in positive sign) and they are located inside the nucleus
- <u>Neutrons</u>: They are uncharged particles and they are located inside the nucleus with the protons
Then the atom contains positive particles and negative particles, it is electrically neutral.
Answer:
The velocity of the shell when the cannon is unbolted is 500.14 m/s
Explanation:
Given;
mass of cannon, m₁ = 6430 kg
mass of shell, m₂ = 73.8-kg
initial velocity of the shell, u₂ = 503 m/s
Initial kinetic energy of the shell; when the cannon is rigidly bolted to the earth.
K.E = ¹/₂mv²
K.E = ¹/₂ (73.8)(503)²
K.E = 9336032.1 J
When the cannon is unbolted from the earth, we apply the principle of conservation of linear momentum and kinetic energy
change in initial momentum = change in momentum after
0 = m₁u₁ - m₂u₂
m₁v₁ = m₂v₂
where;
v₁ is the final velocity of cannon
v₂ is the final velocity of shell

Apply the principle of conservation kinetic energy

Therefore, the velocity of the shell when the cannon is unbolted is 500.14 m/s
The formula for work is N x m, which will equal in joules.
500 x 5 = 2,500 joules