(a)
KE = m v^2 / 2 = (1200 kg)(20 m/s)^2 / 2 = 240,000 J
(b)
The energy is entirely dissipated by the force of friction in the brake system.
(c)
W = delta KE = KEf - KEi = (0 - 240,000) J = -240,000 J
(d)
Fd = delta KE
F = (delta KE) / d = (-240,000 J) / (50 m) = -4800 N
The magnitude of the friction force is 4800 N.
I believe the correct answer is A, Wave 1 has a longer wavelength and a higher amplitude than wave 2. Both A and B are transverse wave, therefore, the wavelength is the distance between two successful crest (highest point) or two successful trough (lowest point). In this case, wave 1 has a longer wavelength than wave 2. Amplitude is the maximum displacement of particles in a wave on either side from the equilibrium point. From the diagram wave 1 as a higher amplitude compared to wave 2.
Density(rho) = m/v
(1.3)/((3.2)(17.1)(3.8))
since density is given in kg/m^3 you should convert the blocks dimensions to meters
1.3/(0.032*0.038*0.171)
plugging in these numbers would give you the density
1.3/0.000208
6250
with sigfigs= 6300kg/m^3
Answer:
it is very hard question for me sorry i cant solve it
Ptolemy believed in the theory that the earth was the center of the universe (geocentric) and it is not moving in the center while Copernicus later proposed otherwise, in his heliocentric theory he believed that the sun was the center of the universe but it was not moving. Both theories were influenced by their observation of how the light shade from the sun changes during the day, and also through observation of other celestial bodies whose light intensity changes which made them arrived to the conclusion that they are not equidistant nor stationary with respect to earth.