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4 years ago

Can you help plz I don’t get it

Mathematics

1 answer:

aleksklad [387]4 years ago

7 0

The correct answer is A) x=3

What this picture demonstrates is 3 x’s on the left side and 9 ones on the right. So it says 3x=9. If you were to divide by 3, or multiply by 1/2, you’d have x=3.

Another way to think of it is by redrawing the picture. Each ‘x’ would get three “1’s” thus x=3

You might be interested in

Whats the answer to 1/2(5×-8)=-9

REY [17]

Answer:

I do not know if that x is a multiply sign or a variable so I'm going to answer both

If the x is a multiplication sign then the answer is -20 = -9

If the x is a variable then the answer is x = -2

Step-by-step explanation:

1/2(5 * -8) = -9

(1 * 5 * -8)/2 = -9

(5 * -8)/2 = -9

-40/2 = -9

-20 = -9

-20 ≠ -9

1/2(5x - 8) = -9

1(5x -8)/2 = -9

(5x - 8)/2 = -9

2((5x - 8)/2) = -9 * 2

2(5x - 8)/2 = -9 * 2

5x - 8 = -9 * 2

5x - 8 = -18

+8 +8

------------------

5x = -10

x = -10/5

x = -2

5 0

3 years ago

PLEASE HELP!!

valkas [14]

A) Here, sum of two non-adjacent angles: 52 + 25 = 77
Now, ∠3 = 180 - 77 [ sum of all angles in a triangle is 180 ]
so, ∠3 = 103

Now, ∠3 + ∠4 = 180 [ Supplementary angles ]
So, ∠4 = 180 - ∠3
∠4 = 180 - 103 = 77
∠4 = 77 [ which is sum of two non-adjacent angles ]

....Hence proved.

b) m∠4 = 77
[ Solved in previous section ]

Hope this helps!

4 0

4 years ago

Read 2 more answers

A 51-foot wire running from the top of a tent pole to the ground makes an angle of 58° with the ground. If the length of the ten

AfilCa [17]

Answer:

35.11 ft

Step-by-step explanation:

This given situation can be thought of as triangle $\triangle PQR$ where PQ is the length of pole.

PR is the length of rope.

and QR is the distance of bottom of pole to the point of fastening of rope to the ground.

And $\angle Q \neq 90^\circ$

Given that:

PQ = 44 ft

PR = 51 ft

$\angle R = 58^\circ$

To find:

Side QR = ?

Solution:

We can apply Sine Rule here to find the unknown side.

Sine Rule:

$\dfrac{a}{sinA} = \dfrac{b}{sinB} = \dfrac{c}{sinC}$

Where

a is the side opposite to $\angle A$

b is the side opposite to $\angle B$

c is the side opposite to $\angle C$

$\dfrac{PR}{sinQ}=\dfrac{PQ}{sinR}\\\Rightarrow sin Q =\dfrac{PR}{PQ}\times sinR\\\Rightarrow sin Q =\dfrac{51}{44}\times sin58^\circ\\\Rightarrow \angle Q =79.41^\circ$

Now,

$\angle P +\angle Q +\angle R =180^\circ\\\Rightarrow \angle P +58^\circ+79.41^\circ=180^\circ\\\Rightarrow \angle P = 42.59^\circ$

Let us use the Sine rule again:

$\dfrac{QR}{sinP}=\dfrac{PQ}{sinR}\\\Rightarrow QR =\dfrac{sinP}{sinR}\times PQ\\\Rightarrow QR =\dfrac{sin42.59}{sin58}\times 44\\\Rightarrow QR = 35.11\ ft$