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Amiraneli [1.4K]
3 years ago
11

A new building is being constructed a distance of 420 feet from the ocean, and the builder wants to have a rooftop patio

Mathematics
1 answer:
Vlad1618 [11]3 years ago
7 0

Answer:

\theta = 4.8^\circ

It is possible

Step-by-step explanation:

Given

See attachment for the construction

Solving (a): The minimum angle

This is calculated as thus:

tan(\theta) = \frac{Opposite}{Adjacent}

tan(\theta) = \frac{15}{180}

tan(\theta) = 0.0833

Calculate \theta

\theta = tan^{-1}(0.0833)

\theta = 4.761

\theta = 4.8^\circ --- approximated

Solving (b):

First; calculate the height of the building using the following equivalent ratio.

h : 420 = 15 : 180

Where h is the height of the building

\frac{h }{ 420 }= \frac{15 }{ 180}

h= \frac{15 }{ 180}*420

h= \frac{15*420 }{ 180}

h= \frac{6300}{ 180}

h= 35

<em>This means that it is possible that the builder builds a 32 feet high building</em>

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14 because 2 people=13 problems in an hour

91/13=7

7times 2 is 14

14 IS YOUR ANSER PLS MARK ME BRAINLIEST :D

4 0
3 years ago
The length of a rectangle is 4 less than twice the width. If the perimeter of the rectangle is 130, find the length of the recta
Alchen [17]

Answer:

Let L be the length of the rectangle and w be the width of the rectangle.

"The lenght of a rectangle is one less than twice the width" means L=2W-1

Using perimeter formula of a rectangle which is P=2(L+W) you have:

P=2(L+W)

130=2(2W-1+W)

Solve equation above to find W

130=2(3W-1)

130=6W-2

130+2=6W

132=6W

W=22

From here you find L=2W-1=2x22-1=43

Only thing left is to find area A=LxW

4 0
3 years ago
PLEASE HELP WILL GIVE TWENTY POINTS Which is the best approximation for the measure of angle ABC?
Shkiper50 [21]
Cos(x) = BC/AB = 10.5/20 = 0.525  ⇒ x = 58.3°
3 0
3 years ago
Resolve into factors:2p(p-1)-p+1
Vlad1618 [11]

Answer:

(2p-1)(p-1)

Step-by-step explanation:

=> 2p(p-1)-p+1

Opening brackets

=> 2p²-2p-p+1

=> 2p²-3p+1

Using mid-term break formula

=> 2p²-2p-p+1

=> 2p(p-1)-1(p-1)

=> (2p-1)(p-1)

5 0
3 years ago
A leather store performs an observational survey of women walking through a mall. There were 30 women that walked by in an hour.
Blababa [14]

Answer:

Step-by-step explanation:

let's call B the event that a woman was wearing a belt and C the event that a woman was carrying a purse.

The probability P(B/C) that a woman was wearing a belt, given that the woman was also carrying a purse can be calculated as:

P(B/C) = P(B∩C)/P(C)

Where P(C) is the probability that a woman was carrying purse and P(B∩C) is the probability that the woman was both carrying purse and wearing belt.

So, P(C) is calculated as:

P(C) = 18 / 30 = 0.6

Because there were 30 women that walked by in an hour and of those women, 18 were carrying purses.

At the same way, P(B∩C) is equal to:

P(B∩C) = 6 / 30 = 0.2

Finally, P(B/C) is equal to:

P(B/C) = 0.2/0.6 = 0.3333

6 0
3 years ago
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