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belka [17]
4 years ago
9

A towel has a repeating pattern of 2 green stripes then 3 blue stripes and then one yellow stripe with tell has 20 Stripes altog

ether how many blue stripes are on it
Mathematics
2 answers:
Anna35 [415]4 years ago
8 0
12 is the answer because when you add the green and blue you get 5 and 5×4= 20 so you multiply the blue by 4 and the green by 4 and add them together which = 20. so 3×4=12 and 2×4=8 so your answer is again 12
MariettaO [177]4 years ago
4 0
GG BBB Y GG BBB Y GG BBB Y GG

9 Blue stripes.
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15 - 9 + 2.65 + 1.35 + 2(1.74)
statuscvo [17]
15 - 9 + 2.65 + 1.35 + 3.48
6 + 2.65 + 1.35 + 3.48
8.65 + 1.35 + 3.48
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13.48
3 0
3 years ago
How do you do simultaneous equations by the method or substitution?​
ozzi

Answer:

Here's the simplest example possible: let's say x + y = 3 and x - y = 1. Solve the second equation for x by adding y to both sides: (x - y) + y = 1 + y. So x = 1 + y. Take that value of x, and substitute it into the first equation given above (x + y = 3).

5 0
3 years ago
Considering a bag of marbles has 5 green marbles, 3 blue marbles, and 2 red marbles. Three marbles are drawn in sequence and are
kipiarov [429]

Answer:

A

Step-by-step explanation:

basta a hehehehhjshshshss

6 0
3 years ago
D<br> Evaluate<br> arcsin<br> (6)]<br> at x = 4.<br> dx
sineoko [7]

Answer:

\frac{1}{2\sqrt{5} }

Step-by-step explanation:

Let, \text{sin}^{-1}(\frac{x}{6}) = y

sin(y) = \frac{x}{6}

\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})

\frac{d}{dx}\text{sin(y)}=\frac{1}{6}

\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx} ---------(1)

\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}

\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}

cos(y) = \sqrt{1-\text{sin}^{2}(y) }

          = \sqrt{1-(\frac{x}{6})^2}

          = \sqrt{1-(\frac{x^2}{36})}

Therefore, from equation (1),

\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}

Or \frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}

At x = 4,

\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}

\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}

                   =\frac{1}{6\sqrt{\frac{36-16}{36}}}

                   =\frac{1}{6\sqrt{\frac{20}{36} }}

                   =\frac{1}{\sqrt{20}}

                   =\frac{1}{2\sqrt{5}}

4 0
3 years ago
What is y-4= -2(x+7) written in standard form
belka [17]

Answer:

2x + y = -10

Step-by-step explanation:

Simplify −2(x+7)

y−4=−2x−14

Move all terms containing variables to the left side of the equation.

2x+y−4= −14

Move all terms not containing a variable to the right side of the equation.

2x + y = −10

Hope this helps

7 0
3 years ago
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