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Alex777 [14]
3 years ago
14

WHY DOES SOLVING RADICAL EQUATIONS NEED A DIFFERENT PROCESS? HOW DO EXTRANEOUS SOLUTIONS ARISE FROM RADICAL EQUATIONS?

Mathematics
1 answer:
professor190 [17]3 years ago
6 0
Solving radical equations are different because you would want to get everything in the equation to rational numbers.
Extraneous solutions arise when you manipulate the equation. After manipulating if a solution is found that can not satisfy the original equation(s).
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a 90% confidence interva is constructed for the population mean. If a 95% confidence interval had been constructed instead (ever
zhuklara [117]

Answer: increased

Step-by-step explanation:

  • An x% confidence interval indicates that a person can be x% confident that true population parameter lies in it.

More level of confidence more width of the interval.

As level of Confidence interval increases width of interval increases.

Width of interval \propto  level of Confidence interval

So, If a 95% confidence interval had been constructed instead of 90% the width of the interval would have been<u> increased.</u>

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3 years ago
What is (4x + 3) + (-2x + 4)
kobusy [5.1K]

Answer:

(4x + 3) + (-2x + 4) = 2x + 7  

Step-by-step explanation:

(4x + 3) + (-2x + 4) =     you then collect like terms  

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= 2x + (3 + 4). step-by-step

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5 0
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Could someone help me with this?
Juli2301 [7.4K]
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4 0
3 years ago
The perimeter of a rectangle is 46in and the diagonal is 17 in
dmitriy555 [2]

Answer + explaination

p=2*(L+l)=46

L+l=46:2

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so 289+2l*L=529

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4 0
3 years ago
Can I please get some help on this...I have tried to many times...
Bezzdna [24]

Answer: A

Step-by-step explanation:

First, the problem is g(f(x)). You would plug in f(x) wherever you see an x in g(x). To find the domain, you take the bottom function, and set it equal to 0.

\sqrt{x-2} =0

When you solve that, you get x=2. You know your domain is x≥2, but there is as asymptote at x=11. That means the graph never reaches x=11, but gets very close. You find that by setting the entire equation equal to 0 and solve from there.

5 0
4 years ago
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