WHY DOES SOLVING RADICAL EQUATIONS NEED A DIFFERENT PROCESS? HOW DO EXTRANEOUS SOLUTIONS ARISE FROM RADICAL EQUATIONS?
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Answer:
One number is and the other number is
Step-by-step explanation:
Let x be the smaller number and y be the bigger number.
x = x
y = 5x
6x + 3y = 3
6x + (3 * 5x) = 3
6x + 15x = 3
(÷3)
2x + 5x = 1
7x = 1
x =
6x + 3y = 3
6() + 3y = 3
+ 3y = 3
3y = 3 -
3y =
Divide both sides by 3 to get 1y:
y =
So one number is and the other number is
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