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Alex777 [14]
3 years ago
14

WHY DOES SOLVING RADICAL EQUATIONS NEED A DIFFERENT PROCESS? HOW DO EXTRANEOUS SOLUTIONS ARISE FROM RADICAL EQUATIONS?

Mathematics
1 answer:
professor190 [17]3 years ago
6 0
Solving radical equations are different because you would want to get everything in the equation to rational numbers.
Extraneous solutions arise when you manipulate the equation. After manipulating if a solution is found that can not satisfy the original equation(s).
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Determine the next three terms in the following sequence
tia_tia [17]

Answer:

A

Step-by-step explanation:

4 0
3 years ago
The water in a reservoir decreased by 47% during a drought. Before the drought, the reservoir held 44,580 acre ft (AF) of water.
RSB [31]


44,580 x 47 %

44,580 x .47 = 20,952.6

So, the water decreased 20,952.6 ft

If you want the water level after the drought just subtract.

44,580 - 20,952.6 =  23,627.4 ft

Hope this helps. :)

5 0
3 years ago
The graph shows the profit per month for the 10 months during which Swanson's Restaurant has been open. Which is a valid predict
Scrat [10]

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about $4,000 - $6,000

Step-by-step explanation:

4 0
3 years ago
PLS HELP!!!!!!!!!!!!!
stepladder [879]
First, multiply the top equation by 2 and bottom by -3.
60x+60y=900
-60x-75y=-1035
————————
-15y=-135
—————-
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6 0
2 years ago
5,25,125 find 10th term
anastassius [24]

Answer:

9765625

Step-by-step explanation:

There is a common ratio between consecutive terms , that is

r = 25 ÷ 5 = 125 ÷ 25 = 5

This indicates the sequence is geometric with n th term

a_{n} = a₁r^{n-1}

where a₁ is the first term and r the common ratio

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a₁₀ = 5 × 5^{9} = 5 × 1953125 = 9765625

6 0
3 years ago
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