Q = p(r + s)
Use the distributive property
Q = pr + ps
Q = p x r + p x s
Q = p x p + r x s
Q = p^2 + rs
Subtract rs from both sides
Q - rs = p^2
Square root both sides
sqrt Q - rs = p
Answer:
Step-by-step explanation:
You have to find a common denominator 1st then add. So 16 is the common denominator the problem should be 2 7/16+1 14/16+8-16= 3 29/16 then you need to divide 29/16 you will have 4 13/16
Answer:
The cost of one unit of electricity is $0.185
Step-by-step explanation:
Amount charged = $120.99
Units of electricity used = 654
The cost of a unit of electricity can be determined by dividing the amount charged by the number of units used.
So that,
cost of one unit of electricity = 
= 0.185
cost of one unit of electricity = $0.185
This implies that the cost of electricity used is charged at $0.185 per unit.
Thus for 654 units of electricity used, the cost would be;
654 x $0.185 = $120.99
No she will not have enough paper because 200 times five is 1000 and if you multiply 23 by 52 is 1196 but I am not fully sure if this answer is right