<h2>
Answer:</h2><h2>
The cost of an advance ticket = $40</h2><h2>
The cost of an same day ticket = $30</h2>
Step-by-step explanation:
There are two types of tickets to a show, advance and same day tickets.
Let the advance ticket be represented as x and same day ticket as y.
The combined cost of one advance ticket and one same-day ticket is $70.
x + y = 70 .... (1)
For one performance 35 Advance tickets and 25 same day tickets were sold the total amount paid for the ticket was 2150
35 x + 25 y = 2150 ... (2)
multiply eq (1) by 25, we get
25 x + 25 y = 1750 ... (3)
subtract eq (3) from (2), we get
10 x = 400,
x = 40, substitute in eq (1)
40 + y = 70
y = 30
The cost of an advance ticket = $40
The cost of an same day ticket = $30
Ok so find how much you earn per year
30 times 35 times 50=amount earned per year=52500 per year
so
1 million=1,000,000
so
52500 times how many years=1,000,000
divide both sides by 52500
how many years=19.04 so about 19 years
Answer:
Approximately 51 Yards
Step-by-step explanation:
You can solve this by cutting the square in half to make a right triangle. Than, you can use the Pythagorean theorem to solve for the hypotenuse.
a^2+b^2=c^2
36^2+36^2=c^2
1296+1296=c^2
2592=c^2
50.9116
Round to the nearest whole number since the question says approximately: 51
Answer:
x = (k-c)/8
Step-by-step explanation:
8x+c= k
Subtract c from each side
8x+c-c= k-c
8x = k-c
Divide each side by 8
8x/8 = (k-c)/8
x = (k-c)/8
Step-by-step explanation:
tan2x = sin2x/cos2x
we know that ,
- sin2x = 2sinxcosx
- sin2x = 2sinxcosx cos2x = cos²x - sin²x
Since, tan2x = 2sinx*cosx/cos²x- sin²x
Dividing by cos²x in numerator and denominator.
We get ,
- tan2x = 2sinx/cosx / 1- sin²x/cos²x
- Since, we get tan2x= 2tanx/1-tan²x
- Option (c) is correct option.