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Assoli18 [71]
2 years ago
12

The radius of a circle is 2.8 cm. Find the circumference to the nearest tenth.

Mathematics
2 answers:
Neporo4naja [7]2 years ago
6 0

Answer: 17.59 cm

Step-by-step explanation: C=2πr=2·π·2.8=17.59292 cm

oee [108]2 years ago
3 0
17.6cm
Formula c(circumference)=2*pie(3.14)*r(radius)
C=2(2.8)(pie)
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Y=1/2x+13
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Answer:

1) y=1/2x+12

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Step-by-step explanation:

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3 years ago
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I need help on this question.
Serga [27]

the slope of the perpendicular line to the line through the two points is 0

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3 years ago
The figure is a parallelogram.one diagonal measures 28 units. Is the figure a rectangle? Explain
guajiro [1.7K]

Answer:

The parallelogram is not rectangle because the sides of the parallelogram do not meet at right angles.

Step-by-step explanation:

Given the parallelogram with sides 20 and 21 units with diagonal length 28 units.

we have to tell it is a rectangle or not.

The given parallelogram is rectangle if the angle at vertices are of 90° i.e the two triangle formed must be right angles i.e it  must satisfy Pythagoras theorem

28^{2}=20^{2}+21^{2}

784=400+441=881

Not verified

∴ The sides of the parallelogram do not meet at right angles.

Hence, the parallelogram is not rectangle because the sides of the parallelogram do not meet at right angles.

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5 0
3 years ago
According to an​ airline, flights on a certain route are on time 80 ​% of the time. suppose 10 flights are randomly selected and
natulia [17]
<span>(a) This is a binomial experiment since there are only two possible results for each data point: a flight is either on time (p = 80% = 0.8) or late (q = 1 - p = 1 - 0.8 = 0.2).
​(b) Using the formula:</span><span>
P(r out of n) = (nCr)(p^r)(q^(n-r)), where n = 10 flights, r = the number of flights that arrive on time:
P(7/10) = (10C7)(0.8)^7 (0.2)^(10 - 7) = 0.2013
Therefore, there is a 0.2013 chance that exactly 7 of 10 flights will arrive on time.
​(c) Fewer than 7 flights are on time means that we must add up the probabilities for P(0/10) up to P(6/10).
Following the same formula (this can be done using a summation on a calculator, or using Excel, to make things faster):
P(0/10) + P(1/10) + ... + P(6/10) = 0.1209
This means that there is a 0.1209 chance that less than 7 flights will be on time.
​(d) The probability that at least 7 flights are on time is the exact opposite of part (c), where less than 7 flights are on time. So instead of calculating each formula from scratch, we can simply subtract the answer in part (c) from 1.
1 - 0.1209 = 0.8791.
So there is a 0.8791 chance that at least 7 flights arrive on time.
(e) For this, we must add up P(5/10) + P(6/10) + P(7/10), which gives us
0.0264 + 0.0881 + 0.2013 = 0.3158, so the probability that between 5 to 7 flights arrive on time is 0.3158.
</span>
6 0
2 years ago
In decimal form, to the nearest tenth, what is the probability that a randomly selected Riverside High School student is in twel
Lunna [17]
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4 0
3 years ago
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