Kevin draws a figure that has 4 sides all sides have the same length his figure has no right angels what figure does he draw

The 1994 Winter Olympics included the aerials competition in skiing. In this event skiers speed down a ramp that slopes sharply

kykrilka [37]

Answer: Got It!

<em>Explanation: </em>let s = speed at launch

v = 0 at top = s sin 63 - g t

so at top

t = s sin 63/g = .0909 s

h = 13.6 = s sin 63 t - 4.9 t^2

13.6 = .081s^2 - .0405 s^2

s^2 = 336

s = 18.3 m/s

0 0

4 0

3 years ago

Calculate the coefficient of friction of a 12kg object that has a force of friction of 3N

postnew [5]

Answer:

0.026

Explanation:

The force of friction acts in the direction perpendicular to the norm force of the surface on which the object rests, induced by gravity. The magnitude of the friction force is

(Friction) = (mass) x (gravitational acceleration g) x (coefficient of friction)

from which the coefficient of friction can be determined:

(coefficient of friction) = (Friction) / ((mass)x(g)) = 3 N / (12 kg * 9.8 m/s^2) = 0.026

3 0

3 years ago

The center of a moon of mass m is a distance D from the center of a planet of mass M. At some distance x from the center of the

nataly862011 [7]

Answer with Explanation:

Let rest mass $m_0$ at point P at distance x from center of the planet, along a line connecting the centers of planet and the moon.

Mass of moon=m

Distance between the center of moon and center of planet=D

Mass of planet=M

We are given that net force on an object will be zero

a.We have to derive an expression for x in terms of m, M and D.

We know that gravitational force= $\frac{GmM}{r^2}$

Distance of P from moon=D-x

$F_m$ =Force applied on rest mass due to m

$F_m$ =Force on rest mass due to mas M

$F_M=F_m$ because net force is equal to 0.

$F_m=F_M$

$\frac{Gm_0m}{(D-x)^2}=\frac{Gm_0M}{x^2}$

$\frac{m}{(D-x)^2}=\frac{M}{x^2}$

$\frac{x^2}{(D-x)^2}=\frac{M}{m}$

$\frac{x}{D-x}=\sqrt{\frac{M}{m}}$

Let $R=\sqrt{\frac{M}{m}}$

Then, $\frac{x}{D-x}=R$

$x=DR-xR$

$x+xR=DR$

$x(1+R)=DR$

$x=\frac{DR}{1+R}$

b.We have to find the ratio R of the mass of the mass of the planet to the mass of the moon when x= $\frac{2}{3}D$

Net force is zero

$F_m=F_M$

$\frac{Gm_0m}{(D-\frac{2}{3}D)^2}=\frac{Gm_0M}{\frac{4}{9}D^2}$

$\frac{m}{\frac{D^2}{9}}=\frac{9M}{4D^2}$

$\frac{M}{m}=4$

Hence, the ratio R of the mass of the planet to the mass of the moon=4:1

8 0

4 years ago

You are standing in an elevator that is accelerating upward at 1m/s². Which of the following pairs of forces is an action-reacti

Lostsunrise [7]

Answer:

B The force that the floor of the elevator exerts on you and the force that you exert on the floor of the elevator

Explanation:

A. is incorrect because the force of gravity on you will always stays the same while the force of the elevator exerts on you changes as it takes you upward

B. is correct in accordance to Newton's 3rd law of action and reaction forces.

C. is incorrect because gravity force stays the same while the force that you exerts on the floor change as elevator moving upward.

D. is incorrect although it states Newton's 1st law. However there can still be pair of forces (part B) that could counter balance each other among other forces.

5 0

3 years ago

Which of the following is not an application of Doppler technology?

allsm [11]

The correct answer to the question above is The third Option: C; ultrasound imaging of the liver. The ultrasound imaging of the liver is definitely not an application of Doppler technology.

Hope this helps! :)

8 0

4 years ago

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