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miss Akunina [59]
4 years ago
5

How is pressure related to force and surface area

Physics
1 answer:
kherson [118]4 years ago
7 0
Pressure is Force per Unit Area.Pressure is the force on an object that is spread over a surface area. The equation for pressure is the forcedivided by the area where the force is applied.
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In an iron rod the particles vibrate. If one end of an iron rod is heated, the vibrating particles transfer energy to neighborin
dalvyx [7]

Answer:

Conduction

Explanation:

Conduction. When a substance is heated, its particles gain internal energy and move more vigorously. The particles bump into nearby particles and make them vibrate more. This passes internal energy through the substance by conduction , from the hot end to the cold end.

6 0
3 years ago
a force is applied to an object at rest with a mass of 100 kg. the same force is applied to an object at rest with a mass of 1 k
Dafna1 [17]
The object with the mass ok 1kg will move more quickly because it is lighter than the 100kg object
3 0
4 years ago
In this setup how can potential energy be converted into kinetic energy .
d1i1m1o1n [39]

Answer:

If force is applied to cause the motion of the body

Explanation:

In the setup given in this diagram, potential energy can be converted into kinetic energy by applying force on the cart or object to move it down the slope.

Potential energy is the energy due to the position of a body. The body has huge potential energy at its current position.

Kinetic energy is the energy due to the motion of a body.

As the body moves down the slope and its velocity increases, it gains massive kinetic energy.

Down the slope, the kinetic energy increases as the potential energy decreases.

At the bottom of the slope, the potential energy becomes zero and the kinetic energy is at its maximum.

7 0
3 years ago
An object moves 4 meters north, then 3 meters east. What is the displacement of the object?
Lady bird [3.3K]

The displacement of the object that moved 4 meters north, then 3 meters east is 5 meters.

<h3>What is displacement?</h3>

Displacement is change in the position of an object. It can be described as the shortest distance between the initial and final position of an object.

The displacement of the object is calculated as follows;

d² = 4² + 3²

d² = 25

d = 5 m

Thus, the displacement of the object that moved 4 meters north, then 3 meters east is 5 meters.

Learn more about displacement here: brainly.com/question/2109763

#SPJ2

4 0
2 years ago
Read 2 more answers
The tape in a videotape cassette has a total
xxMikexx [17]

Answer:

w=19.76 \ rad/s

Explanation:

<u>Circular Motion </u>

Suppose there is an object describing a circle of radius r around a fixed point. If the relation between the angle of rotation by the time taken is constant, then the angular speed is also constant. If that relation increases or decreases at a constant rate, the angular speed is given by:

w=w_o+\alpha \ t

Where \alpha is the angular acceleration and t is the time. If the object was instantly released from the circular path, it would have a tangent speed of:

\displaystyle v_t=w.r

We have two reels: one loaded with the tape to play and the other one empty and starting to fill with tape. They both rotate at different angular speeds, one is increasing and the other is decreasing as the tape goes from one to the other. We'll assume the tangent speed is constant for both (so the tape can play correctly). Let's call w_1 the angular speed of the loaded reel and w_2 that from the empty reel. We have

w_1=w_{o1}+\alpha_1 \ t

w_2=w_{o2}+\alpha_2 \ t

If r_f=35\ mm=0.035\ m is the radius of the reel when it's full of tape, the angular speed for the loaded reel is computed by

\displaystyle w_{01}=\frac{v_t}{r_f}

The tangent speed is computed by knowing the length of the tape and the time needed to fully play it.

t=1.8\ h=1.8*3600=6480\ sec

\displaystyle v_t=\frac{x}{t}=\frac{249\ m}{6480\ sec}=0.0384 \ m/s

\displaystyle w_{01}=\frac{0.0384}{0.035}=1,098 \ rad/s

If r_e=10\ mm=0.001\ m is the radius of the reel when it's empty, the angular speed for the empty reel is computed by

\displaystyle w_{02}=\frac{0.0384}{0.001}=38.426 \ rad/s

The full reel goes from w_{01} to w_{02} in 6480 seconds, so we can compute the angular acceleration:

\displaystyle \alpha_1=\frac{w_{02}-w_{01}}{6480}

\displaystyle \alpha_1=\frac{38.426-1.098}{6480}=0.00576 \ rad/sec^2

The empty reel goes from w_{02} to w_{01} in 6480 seconds, so we can compute the angular acceleration:

\displaystyle \alpha_2=\frac{1.098-38.426}{6480}=-0.00576 \ rad/sec^2

So the equations for both reels are

w_1=1.098+0.00576 \ t

w_2=38.426-0.00576 \ t

They will be the same when

1.098+0.00576 \ t=38.426-0.00576 \ t

Solving for t

\displaystyle t=\frac{38.426-1.098}{0.0115}

t=3240 \ sec

The common angular speed is

w_1=1.098+0.00576 \ 3240=19.76 \ rad/s

w_2=38.426-0.00576 \ 3240=19.76 \ rad/s

They both result in the same, as expected

\boxed{w=19.76 \ rad/s}

6 0
4 years ago
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