Answer:
Solution:
we have given the equation of motion is x(t)=8sint [where t in seconds and x in centimeter]
Position, velocity and acceleration are all based on the equation of motion.
The equation represents the position. The first derivative gives the velocity and the 2nd derivative gives the acceleration.
x(t)=8sint
x'(t)=8cost
x"(t)=-8sint
now at time t=2pi/3,
position, x(t)=8sin(2pi/3)=4*squart(3)cm.
velocity, x'(t)=8cos(2pi/3)==4cm/s
acceleration, x"(t)==8sin(2pi/3)=-4cm/s^2
so at present the direction is in y-axis.
Answer:
2 seconds
Explanation:
The frequency of a wave is related to its wavelength and speed by the equation

where
f is the frequency
v is the speed of the wave
is the wavelength
For the wave in this problem,
v = 2 m/s

So the frequency is

The period of a wave is equal to the reciprocal of the frequency, so for this wave:

This means that the wave takes 4 seconds to complete one full cycle.
Therefore, the time taken for the wave to go from a point with displacement +A to a point with displacement -A is half the period, therefore for this wave:

The leaf fell at the crooked path instead of straight down because air currents and gravity applied changing and unbalanced forces to the leaf.
<h3>What is an air current?</h3>
An air current is defined as the changes in atmospheric pressure that causes the movement of air from one area to another.
When a leaf is detached naturally from the tree, it won't fall straight down to the floor but will fall a distance away from the tree due to the action of air current and some unbalanced forces.
Learn more about leaf here:
brainly.com/question/24234175
#SPJ1
You take the inverse of the total resistances of each branch and add them up.
So if you have 5ohm, 7 ohm, and 10ohm, you would add
1/5 + 1/7 + 1/10 = 31/70
Then flip it back by either using the <span>x<span>−1</span></span><span> (inverse) key on your calculator or simply dividing 70 by 31 to get a total of 2.26ohms</span>
<h2>
Answer:</h2>
The event horizon is the surface of a black hole, it is the border of space-time in which the events on one side of it can not affect an observer on the other side.
That is, at this border also called "point of no return", nothing can escape (not even light) and no event that occurs within it can be seen from outside.