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Zielflug [23.3K]
2 years ago
5

A point charge Q is located a short distance from a point charge 3Q, and no other charges are present. If the electrical force o

n Q is F, what is the electrical force on 3Q?a. 3Fb. √3Fc. F/√3d. Fe. F/3
Physics
1 answer:
weeeeeb [17]2 years ago
7 0

Answer:

d) F

Explanation:

According to columb's law:

"The magnitude of electrostatic force between two charges is directly proportional to the product of magnitude of two charges and inversly proportional to separation between them."

If q₁ and q₂ are magnitude of two charges, d is distance between them and k is dielectric constant, then force F is given by

                                               

                                              F=\frac{kq_{1}q_{2}}{d^2}

According to this force exerted on point charge Q is same as that of 3Q, so force point 3Q charge experience is also F

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5/6 - 1/3 sorry for add part i was meant to do minus but tell me what it is?​
bulgar [2K]

Answer:

\frac{1}{2}

Explanation:

\frac{5}{6} -\frac{1}{3} = \frac{15}{18} -\frac{6}{18}=\frac{9}{18} =\frac{1}{2}

5 0
2 years ago
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Bowling ball and a balloon are dropped from a 50 m tall building at the same time. IN AIR which object will hit the ground firs
HACTEHA [7]

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2 years ago
Two planets in space gravitationally attract each other. if both the masses and distances are doubled, the force between them is
worty [1.4K]
The force btw then remain the same
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3 years ago
A. List at least 5 examples of events or factors that could cause extinction. 
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Disease
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Polution.

8 0
3 years ago
Read 2 more answers
A beam of protons is moving toward a target in a particle accelerator. This beam constitutes a current whose value is. (a) How m
Gelneren [198K]

Answer:

a. 5 × 10¹⁹ protons b. 2.05 × 10⁷ °C

Explanation:

Here is the complete question

A beam of protons is moving toward a target in a particle accelerator. This beam constitutes a current whose value is 0.42 A. (a) How many protons strike the target in 19 seconds? (b) Each proton has a kinetic energy of 6.0 x 10-12 J. Suppose the target is a 17-gram block of metal whose specific heat capacity is 860 J/(kg Co), and all the kinetic energy of the protons goes into heating it up. What is the change in temperature of the block at the end of 19 s?

Solution

a.

i = Q/t = ne/t

n = it/e where i = current = 0.42 A, n = number of protons, e = proton charge = 1.602 × 10⁻¹⁹ C and t = time = 19 s

So n = 0.42 A × 19 s/1.602 × 10⁻¹⁹ C

       = 4.98 × 10¹⁹ protons

       ≅ 5 × 10¹⁹ protons

b

The total kinetic energy of the protons = heat change of target

total kinetic energy of the protons = n × kinetic energy per proton

                                                         = 5 × 10¹⁹ protons × 6.0 × 10⁻¹² J per proton

                                                         = 30 × 10⁷ J

heat change of target = Q = mcΔT ⇒ ΔT = Q/mc where m = mass of block = 17 g = 0.017 kg and c = specific heat capacity = 860 J/(kg °C)

ΔT = Q/mc = 30 × 10⁷ J/0.017 kg × 860 J/(kg °C)

     = 30 × 10⁷/14.62

     = 2.05 × 10⁷ °C

5 0
2 years ago
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