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Firdavs [7]
2 years ago
9

NEED HELP!!! IF YOU ANSWER ALL QUESTIONS I WILL GIVE YOU BRAINEST!!!!! 15 POINTS!!!!

Physics
2 answers:
SVETLANKA909090 [29]2 years ago
8 0

Answer: A, D, A

Explanation:

marissa [1.9K]2 years ago
8 0

Answer:

1.  D

2. A

3. A

Explanation:

This is what i think. If it is not right, I am sorry. Hopefully, this will help you!

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Cars A and B are racing each other along the same straight road in the following manner: Car A has a head start and is a distanc
kumpel [21]

Answer:\frac{D_A}{v_B-v_A}

Explanation:

Given

car A had a head start of D_A

and it starts at x=0 and t=0

Car B has to travel a distance of D_A and d_a

where d_a is the distance travel by car A in time t

distance travel by car A is

d_a=v_A\times t

For car B with  speed v_B

d_B=D_A+d_a

v_B\times t=D_A+v_A\times t

t=\frac{D_A}{v_B-v_A}

7 0
3 years ago
Solve the question that follows using the equation for the conversion of Celsius to Fahrenheit. F=95(C)+32 On February 9, 1934,
SVEN [57.7K]

Answer:

Buffalo, NY

Explanation:

Temperature in Buffalo, NY = -29°C

In order to compare the temperatures we need to convert them to the same scale.

F=\dfrac{9}{5}C+32\\\Rightarrow F=\dfrac{9}{5}\times -29+32\\\Rightarrow F=-20.2

So, the temperature in Buffalo, NY was -20.2°F and the temperature in Anchorage, AL was 19°F.

Hence, it was colder in Buffalo, NY than in Anchorage, AL.

3 0
3 years ago
What do folds on a strip of paper mean
Vlad [161]
There are creases. Or just origami
7 0
2 years ago
Lemon trees receiving the most water produced the most lemons. What is the independent variable, the dependent variable, and the
Veseljchak [2.6K]
The lemon trees will always be the same so they are the constants. The independent variable is the water amount because it is changing. The dependent variable is the amount of lemons because it is the variable being tested. (If we change the amount of water how many lemons will be produced?)

3 0
3 years ago
Over an interval of 4.0 s the average rate of change of the concentration of B was measured to be -0.0760 M/s. What is the final
Serhud [2]

Complete question:

Consider the hypothetical reaction 4A + 2B → C + 3D

Over an interval of 4.0 s the average rate of change of the concentration of B was measured to be -0.0760 M/s. What is the final concentration of A at the end of this same interval if its concentration was initially 1.600 M?

Answer:

the final concentration of A is 0.992 M.

Explanation:

Given;

time of reaction, t = 4.0 s

rate of change of the concentration of B =  -0.0760 M/s

initial concentration of A = 1.600 M

⇒Determine the rate of change of the concentration of A.

From the given reaction: 4A + 2B → C + 3D

2 moles of B ---------------> 4 moles of A

-0.0760 M/s of B -----------> x

x = \frac{4(-0.076)}{2} \\\\x = -0.152 \ M/s

⇒Determine the change in concentration of A after 4s;

ΔA = -0.152 M/s  x 4s

ΔA = -0.608 M

⇒ Determine the final concentration of A  after 4s

A = A₀ + ΔA

A = 1.6 M + (-0.608 M)

A = 1.6 M - 0.608 M

A = 0.992 M

Therefore, the final concentration of A is 0.992 M.

5 0
2 years ago
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