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egoroff_w [7]
2 years ago
8

What happens to a star after it goes supernova? Does the remnant of the star form a dwarf star, neutron star, black hole, or som

ething else? Thanks!!!
Physics
2 answers:
qaws [65]2 years ago
8 0
I believe it forms a black hole. Eek!
il63 [147K]2 years ago
8 0
Well after the star goes supernova, It becomes a Neutron Star, an extrememly powerful and dense Explosion full of atoms and neutrons, if the mass does not exceed than it will remain to be a neutron star. Hope that helps
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A track athlete jumps over a hurdle. What is the equal and opposite force for the force of the athlete pushing on the ground as
Jet001 [13]

Answer: Normal Force of the ground pushing the athlete up.

Explanation: I did this on Khan Academy and got the answer right.

6 0
3 years ago
Find the Force a Watermelon hits the ground with when it is dropped off a roof and has a mass of 18 kg
ANEK [815]

Answer:

Explanation:

Weight = Force

Weight = mass x gravity

Weight = 18 kg x 9.81

Weight = 176.58 N

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2 years ago
A wave has a frequency of 440 hz and a wavelength of 0.77m. What is the velocity of the wave
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Answer:velocity of wave

=338.8 m/s

Explanation:

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3 years ago
A linebacker runs at 3 m/s and collides with a running back running towards him at 3.2
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Answer:b

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im in fifth grade so i guessd. gl tho heh.

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2 years ago
How much time will have passed by the time a sample of an isotope has decayed to 6.25% of its original mass if the half-life is
aleksandrvk [35]

Answer:

60 days.

Explanation:

Let the original mass (N₀) = 1 g

Amount remaining (N) = 6.25% of its original mass

= 6.25% × 1

= 6.25/100 × 1

= 0.0625 g

Half life (t½) = 15 days

Time (t) =?

Next, we shall determine the rate of decay. This can be obtained as follow:

Decay constant (K) = 0.693/ half life

K = 0.693 / t½

Half life (t½) = 15 days

Decay constant (K) =?

K = 0.693 / t½

K = 0.693 / 15

K = 0.0462 / day

Finally, we shall determine the time taken for the sample of the isotope to decay to 6.25% of its original mass.

This can be obtained as follow:

Original amount (N₀) = 1 g

Amount remaining (N) = 0.0625 g

Decay constant (K) = 0.0462 / day

Time (t) =?

Log (N₀/N) = Kt/2.3

Log (1/0.0625) = 0.0462 × t / 2.3

Log 16 = 0.0462 × t / 2.3

1.2041 = 0.0462 × t /2.3

Cross multiply

0.0462 × t = 1.2041 × 2.3

Divide both side by 0.0462

t = (1.2041 × 2.3)/0.0462

t = 59.9 ≈ 60 days

Therefore, the time taken for the sample of the isotope to decay to 6.25% of its original mass is 60 days

5 0
3 years ago
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