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egoroff_w [7]
3 years ago
8

What happens to a star after it goes supernova? Does the remnant of the star form a dwarf star, neutron star, black hole, or som

ething else? Thanks!!!
Physics
2 answers:
qaws [65]3 years ago
8 0
I believe it forms a black hole. Eek!
il63 [147K]3 years ago
8 0
Well after the star goes supernova, It becomes a Neutron Star, an extrememly powerful and dense Explosion full of atoms and neutrons, if the mass does not exceed than it will remain to be a neutron star. Hope that helps
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A mass of 10 g of oxygen fill a weighted piston–cylinder device at 20 kPa and 110°C. The device is now cooled until the tempe
mezya [45]

Answer:

The change of the volume of the device during this cooling is 14.3\times10^{-3}\ m^3

Explanation:

Given that,

Mass of oxygen = 10 g

Pressure = 20 kPa

Initial temperature = 110°C

Final temperature = 0°C

We need to calculate the change of the volume of the device during this cooling

Using formula of change volume

\Delta V=V_{2}-V_{1}

\Delta V=\dfrac{mR}{P}(T_{2}-T_{1})

Put the value into the formula

\Delta V=\dfrac{0.3125\times0.0821}{2.0265\times10^{9}}(383-273)

\Delta V=14.297\ L

\Delta V=14.3\times10^{-3}\ m^3

Hence, The change of the volume of the device during this cooling is 14.3\times10^{-3}\ m^3

6 0
3 years ago
If you were asked to describe metals and magnetism you could say?
Anettt [7]
Some metals having unpaired electrons contain a strong magnetic response, i.e, they can be magnetized by an external magnetic field.
5 0
3 years ago
Ohm’s law describes the relationship between which quantities?
VladimirAG [237]
I think its between b or c
5 0
3 years ago
Read 2 more answers
A 10 kg ball is traveling at the same speed as a 1 kg ball. Compared to the 10 kg ball, the 1 kg ball has
Zepler [3.9K]

The answer is the second option, or 1/10 the same momentum.

7 0
3 years ago
Read 2 more answers
Greyhound pursues a hare and takes 5 leaps for every 6 leaps of the hare, but
maw [93]

{\large{\bold{\rm{\underline{Given \; that}}}}}

★ A grey hound pursues a hare and takes 5 leaps for every 6 leaps of the hare, but 3 leaps of the hound are equal to 5 leaps of the hare.

{\large{\bold{\rm{\underline{To\; find}}}}}

★ The speed of the hound and the hare

{\large{\bold{\rm{\underline{Solution}}}}}

★ The speed of the hound and the hare = 25:18

{\large{\bold{\rm{\underline{Full \; Solution}}}}}

\dashrightarrow  As it's given that a grey hound pursues a hare and takes 5 leaps for every 6 leaps of the hare, but 3 leaps of the hound are equal to 5 leaps of the hare.

 So firstly let us assume a metres as the distance covered by the hare in one leap.

Ok now let's talk about 5 leaps,.! As it's cleared that the hare cover the distance of 5a metres.

 But 3 leaps of the hound are equal to 5 leaps of the hare.

Henceforth, (5/3)a meters is the distance that is covered by the hound.

 Now according to the question,

Hound pursues a hare and takes 5 leaps for every 6 leaps of the hare..! (Same interval)

Now the distance travelled by the hound in it's 5 leaps..!

  • (5/3)a × 5

  • 25/3a metres

 Now the distance travelled by the hare in it's 6 leaps..!

  • 6a metres

 Now let us compare the speed of the hound and the hare. Let us calculate them in the form of ratio..!

  • 25/3a = 6a

  • 25/3 = 6

  • 25:18
5 0
3 years ago
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