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Burka [1]
4 years ago
9

Solve the system of linear equations by substitution check your solution show work

Mathematics
1 answer:
tia_tia [17]4 years ago
8 0
1. Plug in 3x + 11 where the Y is and solve for X.

3x + 11 - x = 23
2x = 12 
x = 6

Now plug back in.

y - 6 = 23
y = 23 + 6
y = 29. 

Your answer is (6, 29), option B

I can't tell what the second system of equations even is. 2x - y = 30? x - y = 30? The second equation doesn't look like it has a x-variable. It's spaced out weird. Can you just ask that in a separate question or type it in the replies? 
You might be interested in
Find the surface area:
ANTONII [103]

Answer:

120 in

Step-by-step explanation:

(5 in * 12 in)/2 = 30 in

30 in * 4 = 120 in

I hope that helps :D

8 0
3 years ago
Read 2 more answers
16. Classify the equation 6(x + 2) = 5(x + 7) as having one solution,
Gnoma [55]

Answer:

23

Step-by-step explanation:

6x+12=5x+35

x=23

4 0
3 years ago
Math help what is the answer will give brainliest.
artcher [175]
The two equations are
x + y = 7
and
4x + 2.5y = 22
the first equation can be solved for x to be
x = 7 - y
next you can substitute x in the second equation
4(7 - y) + 2.5y = 22
Distribute 4 to everything in the parentheses
28 - 4y + 2.5y = 22
combine like terms:
28 - 1.5y = 22
subtract 28 from both sides of the equation
- 1.5y =  - 6
divide both sides by -1.5
y =  4
plug this in to the original equation of x+y=7
x + 4 = 7
subtract 4 from both sides.
x = 3
Final Answer: they bought 3 adult tickets and 4 student tickets


Hope this helps!
7 0
4 years ago
⚠️ Help I don’t understand this one and it’s my last one !! ⚠️
Kruka [31]

Answer:

x=4

Step-by-step explanation:

no because x=4 and you can't have multiple answerd

7 0
3 years ago
Write an inequality from (–5) to (–1) inclusive
skad [1K]

Answer:

-5\leq x\leq -1

Step-by-step explanation:

This is a compound inequality that basically states that the X value is greater than or equal to -5, but less than or equal to -1. It is inclusive, because it includes both numbers and therefore should have an equal to sign (\leq   or \geq) instead of just less than or greater than ( < or >).

8 0
4 years ago
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