Answer:
v_s = 34.269 m / s
Explanation:
This is a Doppler effect exercise, in this case the observer is fixed and the sound source is moving.
f ’= f
where the negative sign is used for when the source approaches the observer and the positive sign for when the source moves away from the observer
In this case when f ’= 5500 Hz approaches and when f’ = 4500 Hz moves away, let's write the two expressions together
5500 = f (
)
4500 = f (
)
let's solve these two equations
1.222 (v-v_s) = v + v_s
v_s (1+ 1.22) = v (1.222 -1)
v_s = v
the speed of sound in air is v = 343 m / s
v_s = 343 0.09990
v_s = 34.269 m / s
The fact that a double convex lens is thicker across its middle is an indicator that it will converge rays of light that travel parallel to its principal axis. A double convex lens is a converging lens. A double concave lens is also symmetrical<span> across both its </span>horizontal<span>and vertical axis.
This is from google btw.</span>
The answer is C. As the frequency of the waves increases, a greater number of wavelengths pass a given point per second. From the wave formula, we see that there is an indirect relationship between frequency and the wavelength. thus, as the frequency increases the wavelength decreases resulting to a smaller distance between the waves which will show greater number of wavelengths between waves.
To solve this problem, let us consider that the Earth is the
origin, the initial reference point. Therefore the speed of rocket plus the
missile would be 0.8 C
Now after the rocket had moved away from Earth, it fired a missile
at a speed of 0.7 C. Now the reference made to this is relative to the rocket.
We have established that our initial reference point is the Earth, therefore
the real speed of the missile with reference to Earth is:
Speed of missile relative to Earth = 0.8 C + 0.7 C
Speed of missile relative to Earth = 1.5 C
Answer is:
<span>A</span>
Yes,and because not everyone can wink and often that someone can only wink with one eye only