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Kitty [74]
3 years ago
9

A wheel is rotating counterclockwise, which we will define as the positive direction, at an angular velocity of 2 rad/s. If the

wheel then experiences a clockwise angular acceleration of 1 rad/s2, what is the wheel’s angular velocity 3 seconds later
Physics
1 answer:
Flauer [41]3 years ago
5 0

Answer:1 rad/s clockwise

Explanation:

Given

angular velocity(\omega _0)=+2 rad/s (ccw)

angular acceleration \alpha =-1 rad/s^2

wheel velocity after t=3 s

we know

\omega =\omega _0+\alpha \cdot t

where \omega =final\ angular\ velocity

\omega _0=initial\ angular\ velocity

\alpha =angular\ acceleration

t=time

\omega =2-1\times 3=-1 rad/s

i.e.\omega =1 rad/s clockwise

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A solenoid with 3,000.0 turns is 70.0 cm long. If its self-inductance is 25.0 mH, what is its radius? (The value of μ0 is 4π x 1
nevsk [136]

Answer:

A. 2.2*10^-2m

Explanation:

Using

Area = length x L/ uo xN²

So A = 0.7m * 25 x 10^-3H /( 4π x10^-7*

3000²)

A = 17.5*10^-3/ 1.13*10^-5

= 15.5*10^-2m²

Area= π r ²

15.5E-2/3.142 = r²

2.2*10^2m

Explanation:

5 0
3 years ago
A 5 kg ball is sitting on the floor without moving. What is the momentum of the ball?
natita [175]

Answer:

The ball has no momentum

Explanation:

The given parameters are;

The mass of the ball = 5 kg

The velocity of the ball = 0 (The ball is sitting on the floor without moving)

The momentum of the ball = The mass of the ball × Velocity of the ball

Therefore, the momentum of the ball = 5 kg × 0 m/s = 0

The momentum of the ball is zero, the ball has no momentum.

5 0
3 years ago
Two point charges are fixed on the y axis: a negative point charge q1 = -25 μC at y1 = +0.18 m and a positive point charge q2 at
dedylja [7]

Answer:

50.91 \mu C

Explanation:

The magnitude of the net force exerted on q is known, we have the values and positions for q_{1} and q. So, making use of coulomb's law, we can calculate the magnitude of the force exerted byq_{1} on q. Then we can know the magnitude of the force exerted by q_{2} about q, finally this will allow us to know the magnitude of q_{2}

q_{1} exerts a force on q in +y direction, and q_{2} exerts a force on q in -y direction.

F_{1}=\frac{kq_{1} q }{d^2}\\F_{1}=\frac{(8.99*10^9)(25*10^{-6}C)(8.4*10^{-6}C)}{(0.18m)^2}=58.26 N\\

The net force on q is:

F_{T}=F_{1} - F_{2}\\25N=58.26N-F_{2}\\F_{2}=58.26N-25N=33.26N\\\mid F_{2} \mid=\frac{kq_{2}q}{d^2}

Rewriting for q_{2}:

q_{2}=\frac{F_{2}d^2}{kq}\\q_{2}=\frac{33.26N(0.34m)^2}{8.99*10^9\frac{Nm^2}{C^2}(8.4*10^{-6}C)}=50.91*10^{-6}C=50.91 \mu C

8 0
4 years ago
What property do the following elements have in common? Li, C, and F A) They are poor conductors of electricity. B) Each element
Aloiza [94]

Answer: Option (D) is the correct answer.

Explanation:

The given elements Li, C and F are all second period elements. So, when we move from left to right across a period then there occurs increase in number of valence electrons as there occurs increase in total number of electrons.

So, it means more electrons are added to the same energy level.

Thus, we can conclude that a property of valence electrons for each element is located in the same energy level is common in the given elements.

7 0
3 years ago
Read 2 more answers
Name two kinds of longitudinal waves and explain how you know they are longitudinal.
dezoksy [38]
A transverse wave and a longitudinal wave.

Transverse:wave particles move at medium speed in perpendicular to the direction that the waves move

Longitudinal:wave particles move at medium speed in parallel to the direction that the wave moves

Hope this helps ^-^
8 0
3 years ago
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