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4 years ago

12

A satellite is in a circular orbit around the earth. the period of the satellite is 25.4 hr. calculate the radius of the orbit o

f the satellite. data: mass of the earth = 5.98 x 1024 kg.

1 answer:

azamat4 years ago

8 0

Satellite X has a greater period an a slower tangential speed than satellite Y

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What does frequency describe

Oxana [17]

Another term used to describe a wave is frequency. Since waves are moving, we define frequency as the number of waves that pass a given point in a specified unit of time. The unit commonly used is Hertz which is the number of wave cycles pass a point in one second. So one cycle per second equals one Hertz. .

4 0

3 years ago

A galaxy that is a featureless spherical ball of stars would be called a type

satela [25.4K]

Answer:

E0

Explanation:

Yes. The "0" indicates that it is spherical

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3 years ago

In a hydroelectric power plant, water flows from an elevation of 400 ft to a turbine, where electric power is generated. For an

VashaNatasha [74]

Answer:

$V=3.475ft^3/s=3.48ft^3/s$

Explanation:

We have here values from SI and English Units. I will convert the units to English Units.

We hace for the power P,

$P= 100kW \rightarrow 100kW*(\frac{737.56ft.lbf/s}{1kW})$

$P= 73.7*10^{3}ft.lbf/s$

we have other values such $h=400ft$ and $\gamma= 62.42lb/ft^3$ (specific weight of the water), and 0.85 for \eta

We need to figure the flow rate of the water (V) out, that is,

$V=\frac{P}{\gamma h \eta_0}$

Where $\eta_0$ is the turbine efficiency, at which is,

$\eta_0 = \frac{P}{\gamma Vh}$

Replacing,

$V=\frac{73.7*10^{3}}{62.42*400*0.85}$

$V=3.475ft^3/s$

With this value (the target of this question) we can also calculate the mass flow rate of the waters,

through the density and the flow rate,

$m=\rho V\\m= 3.475*1.94 \\m=6.7415 slugs/s$

converting the slugs to lbm, 1slug = 32.174lbm, we have that the mass flow rate of the water is,

$m= 217lbm/s$

6 0

3 years ago

An ant is on the pendulum bob of the clock. What would be the displacement in one time period?

Dennis_Churaev [7]

At the end of one full time period, the ant has returned to where it was at the beginning of the time period. Its displacement is <em>zero</em>.

6 0

3 years ago

Using newtons law How much force is accelerated a 66kg skier 2m/s2

Evgen [1.6K]

Answer:

SUPONIENDO QUE NO HAY FRICCIÓN

Explanation:

F = 66 kg( $2 m/s^{2}$ ) = 132 N

8 0

3 years ago