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2 years ago

A jet airplane has a velocity of 1145 knots. A knot is 1 nautical mile (nm)/hr. A nautical

Physics

1 answer:

Tanya [424]2 years ago

4 0

Answer:

1 m = 39.37 in = 39.37/12 ft = 3.28 ft

V = 1145 k/hr = 1145k/hr * 6076 ft/k = 6957020 ft / hr

V = 6957020 ft/hr / 3600 s/hr = 1933 ft/sec

V = 1933 ft/sec / (3.28 ft / m) = 589 m/s

Check:

88 ft/sec = 60 mph

(1145 k/hr * 6076 ft / k) 3600 sec/hr = 1933 ft/sec = 589 m/s

1933 ft/sec / (88 ft/sec) * 60 mph = 1318 mph

Also, 1318 / 1145 = 6076 / 5280 as it should

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A subway train accelerates from rest at one station at a rate of 1.30 m/s^2 for half of the distance to the next station, then d

Minchanka [31]

This problems a perfect application for this acceleration formula:

   Distance = (1/2) (acceleration) (time)² .

During the speeding-up half:   1,600 meters = (1/2) (1.3 m/s²) T²
During the slowing-down half: 1,600 meters = (1/2) (1.3 m/s²) T²

Pick either half, and divide each side by 0.65 m/s²:

   T² = (1600 m) / (0.65 m/s²)

   T = square root of (1600 / 0.65) seconds

Time for the total trip between the stations is double that time.

   T = 2 √(1600/0.65) = <em>99.2 seconds</em> (rounded)

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3 years ago

Which organelle is the powerhouse of the cell, the site of cellular respiration? A) 2 - nucleus B) 5 - endoplasmic reticulum C)

Paladinen [302]

D) 9- mitochondria
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3 years ago

The area of the piston to the master cylinder in a hydraulic braking system of a car is 0.4 square inches. If a force of 6.4 lb

Anit [1.1K]

Answer:

The force applied on one wheel during braking = 6.8 lb

Explanation:

Area of the piston (A) = 0.4 $in^{2}$

Force applied on the piston(F) = 6.4 lb

Pressure on the piston (P) = $\frac{F}{A}$

⇒ P = $\frac{6.4}{0.4}$

⇒ P = 16 $\frac{lb}{in^{2} }$

This is the pressure inside the cylinder.

Let force applied on the brake pad = $F_{1}$

Area of the brake pad ( $A_{1}$ )= 1.7 $in^{2}$

Thus the pressure on the brake pad ( $P_{1}$ ) = $\frac{F_{1} }{A_{1} }$

When brake is applied on the vehicle the pressure on the piston is equal to pressure on the brake pad.

⇒ P = $P_{1}$

⇒ 16 = $\frac{F_{1} }{A_{1} }$

⇒ $F_{1}$ = 16 × $A_{1}$

Put the value of $A_{1}$ we get

⇒ $F_{1}$ = 16 × 1.7

⇒ $F_{1}$ = 27.2 lb

This the total force applied during braking.

The force applied on one wheel = $\frac{F_{1} }{4}$ = $\frac{27.2}{4}$ = 6.8 lb

⇒ The force applied on one wheel during braking.

7 0

2 years ago

A 120-V motor has mechanical power output of 2.50hp. It is 90.0% efficient in converting power that it takes in by electrical tr

EastWind [94]

The current in this motor is equal to 17.27 Ampere.
The energy delivered to this motor in 3.00 hours is equal to 22.38 Megajoules.
At $0.110/kWh, the cost to run the motor for 3.00 hours is equal to $0.684.

<h3>How to determine the current (in A) delivered to the motor?</h3>

Assuming this electric motor is a single-phase motor and it operates by using DC current, its mechanical power output would be given by:

W = ηIV

Making current (I) the subject of formula, we have:

I = ηV/W

Substituting the given parameters into the formula, we have;

I = (2.50 × 0.746 × 1000)/(0.9 × 120)

I = 1,865/108

Current, I = 17.27 Ampere.

For the energy delivered to this motor, we have:

First of all, we would determine the power delivered to this motor as follows:

Power, P = IV

Power, P = 17.27 × 120

Power, P = 2,072.4 Watt.

Therefore, the energy delivered to this motor in 3.00 hours is given by:

Energy = power × time

Energy = 2,072.4 × 3.00 × 3,600 × 1/1000000

Energy = 22.38 Megajoules.

<h3>How to determine the cost?</h3>

At $0.110/kWh, the cost to run the motor for 3.00 hours is given by:

Cost = 0.110 × 22.38 × 0.278

Cost = $0.684.

Read more on energy here: brainly.com/question/15567897

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Complete Question:

A 120-V motor has mechanical power output of 2.50 hp. It is 90.0% efficient in converting power that it takes in by electrical transmission into mechanical power.

(a) Find the current in the motor.

(b) Find the energy delivered to the motor by electrical transmission in 3.00 h of operation.

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1 year ago

A thin partition divides a thermally insulated vessel into a lower compartment of volume V and an upper compartment of volume 2V

Anni [7]

Answer:

1.89mol

Explanation:

The entropy change during free expansion is express as

$S_{f}-S_{i}=nRln(\frac{V_{F}}{V_{I}})\\$