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3 years ago

A jet airplane has a velocity of 1145 knots. A knot is 1 nautical mile (nm)/hr. A nautical

Physics

1 answer:

Tanya [424]3 years ago

4 0

Answer:

1 m = 39.37 in = 39.37/12 ft = 3.28 ft

V = 1145 k/hr = 1145k/hr * 6076 ft/k = 6957020 ft / hr

V = 6957020 ft/hr / 3600 s/hr = 1933 ft/sec

V = 1933 ft/sec / (3.28 ft / m) = 589 m/s

Check:

88 ft/sec = 60 mph

(1145 k/hr * 6076 ft / k) 3600 sec/hr = 1933 ft/sec = 589 m/s

1933 ft/sec / (88 ft/sec) * 60 mph = 1318 mph

Also, 1318 / 1145 = 6076 / 5280 as it should

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3 years ago

You have a 1.55 kg block of silver at room temperature of 20 °C. Silver melts at 962°C. How much heat energy would be needed to

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4 years ago

During a testing process, a worker in a factory mounts a bicycle wheel on a stationary stand and applies a tangential resistive

Alex

Answer:

616.223684211 N

Explanation:

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F = Force acting on sprocket

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$r_1$ = Radius of wheel = 25 cm

Moment of inertia is given by

$I=mr_1^2\\\Rightarrow I=1.7\times 0.25^2\\\Rightarrow I=0.10625\ kgm^2$

Torque

$\tau=I\alpha\\\Rightarrow \tau=0.10625\times 4.9\\\Rightarrow \tau=0.520625\ Nm$

Torque is given by

$\tau=Fr_2-F_rr_1\\\Rightarrow F=\dfrac{\tau+F_rr_1}{r_2}\\\Rightarrow F=\dfrac{0.520625+115\times 0.25}{0.0475}\\\Rightarrow F=616.223684211\ N$

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3 years ago

What average force is needed to accelerate a 9.20-gram pellet from rest to 125 m/s over a distance of 0.800 m along the barrel o

aleksklad [387]

Given:
u = 0, initial velocity
v = 125 m/s, final velocity
s = 0.0800 m, distance traveled
9.20 g, the mass of the pellet

If the acceleration is a, then
0² + 2*(a m/s²)*(0.800 m) = (125 m/s)²
1.6a = 15625
a = 9765.625 m/s²

Calculate the force.
F = (9.20 x 10⁻³ kg)*(9765.625 m/s²) = 98.84 N

Answer: 98.8 N (nearest tenth)

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3 years ago