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3 years ago

Solve step by step2(p+8)=26

Mathematics

2 answers:

romanna [79]3 years ago

8 0

Answer:

Step-by-step explanation:

$2(p+8)=26\qquad\text{divide both sides by 2}\\\\\dfrac{2\!\!\!\!\diagup^1(p+8)}{2\!\!\!\!\diagup_1}=\dfrac{26\!\!\!\!\!\diagup^{13}}{2\!\!\!\!\diagup_1}\\\\p+8=13\qquad\text{subtract 8 from both sides}\\\\p=5$

Natalija [7]3 years ago

7 0

Answer:5

Step-by-step explanation:

2(p+8)=26

2p+16=26

subtract 16 on both sides

you get 2p=10

divide 2 on both sides and get 5

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Please solve -4(x+10) is greater than or equal to -7x + 65

Novay_Z [31]

Answer:

x>=35

Step-by-step explanation:

-4(x+10)>= -7x + 65

-4x-40>= -7x+65

-4x+7x>=65+40

3x>=105

x>=105/3

x>=35

7 0

3 years ago

8. Is the following statement true or false? Justify your conclusion. If a and b are nonnegative real numbers and a + b =0, then

atroni [7]

Answer:

If $a + b = 0$ then $a = 0$ and $b =0$

a | b | a + b (answer)

0 | 0 | 0

0 | 1 | 1

0 | 2 | 2

1 | 0 | 1

2 | 0 | 2

1 | 1 | 2

2 | 1 | 3

Step-by-step explanation:

Considering the following conditions for the real numbers:

$a\geq 0\\b\geq 0$

Following the rules of these in-equations, it is possible to deduce:

$a + b \geq 0$

Then, if the proposed statement is:

$a + b = 0$

The conditions above shall comply the requirements established, but first, analyzing the statement:

If $a \geq 0$ and $b \geq 0$ then $a + b \geq a$ , $a + b \geq b$ and $a + b \geq 0$ .

If $a = 0$ and b a non negative real number, then $a + b \geq b$ , but because to $a = 0$ , then $a + b = b$ . Due to the commutative property of sums, the same behavior will be presented if $b = 0$ and a a non negative real number.