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3 years ago

How did Einstein reconcile the ideas that motion is relative and the speed of light is a constant?

2 answers:

6 0

Einstein reconciled these ideas by describing space and time as parts of a whole called space-time. He explained that space and time, the factors that determine motion or speed, are relative because the speed of light is constant.

yulyashka [42]3 years ago

4 0

Answer:

Sample answer on edge:

Space and time are parts of a whole called space-time. The factors that determine speed are space and time. Space and time are relative because the speed of light is the same in all reference frames.

Explanation:

its the answer on edge lol

You might be interested in

Jules verne wrote a book called twenty thousand leagues under the sea. is the ocean really that deep?explain.

svetoff [14.1K]

no... probably not, jules verne is most likely using HYPERBOLE to prove a point that the ocean is VERY deep.

7 0

4 years ago

The Sun’s surface temperature is about 5800 K and its spectrum peaks at 5000 Å. An O-type star’s surface temperature may be 40,0

vova2212 [387]

Answer:

Part a)

$\lambda_2 = 725 A^o$

Part b)

This range of wavelength exist in the region of X rays

So correct answer will be X Rays

Part c)

No it is not visible because this energy can not travel to large distance

Explanation:

Part a)

As per Wein's law we know that

$\lambda_1T_1 = \lambda_2 T_2$

so we know that

$\lambda_1 = 5000A^o$

$T_1 = 5800 K$

$T_2 = 40,000 K$

now we have

$\lambda_2 = \frac{5000 \times 5800}{40,000}$

$\lambda_2 = 725 A^o$

Part b)

This range of wavelength exist in the region of X rays

So correct answer will be X Rays

Part c)

No it is not visible because this energy can not travel to large distance

7 0

3 years ago

Use Coulomb’s law to derive the dimension for the permittivity of free space.

MrRa [10]

Answer:

Coulomb's law is:

$F = \frac{1}{4*pi*e0} *(q1*q2)/r^2$

First, force has units of Newtons, the charges have units of Coulombs, and r, the distance, has units of meters, then, working only with the units we have:

N = (1/{e0})*C^2/m^2

then we have:

{e0} = C^2/(m^2*N)

And we know that N = kg*m/s^2

then the dimensions of e0 are:

{e0} = C^2*s^2/(m^3)

(current square per time square over cubed distance)

And knowing that a Faraday is:

F = C^2*S^2/m^2

The units of e0 are:

{e0} = F/m.

7 0

3 years ago

You look in the sky and see two jetliners that you know are of equal size, yet one appears to be much larger. Because of your kn

Ksju [112]

Answer:

Because of the knowledge of relative size, it will be assumed that the smaller jetliner is farther away.

Explanation:

According to the theory of relative size, the distance that an object has to the viewing individual affects the perception of the individual regarding the size of the object.

As stated in this case, one of the jetliners is farther away from the other. Therefore, even if the jets are of equal size, the one that is at a greater distance is perceived to be smaller as it is at a greater viewing range. The one that is nearer to the individual seems bigger in comparison to the one farther away due to a closer viewing range.

Therefore, the jet that is nearer appears larger.

To know more about relative size, refer to:

brainly.com/question/19998265

#SPJ4

8 0

2 years ago

Help help help help help

nalin [4]

I am not sure on the rest but the answer to question 4 is volts. sorry i couldn’t be of more help!

3 0

3 years ago